If the following program (myprog) is run from the command line as 

myprog 1 2 3 

what would be the output?

main(int argc, char *argv[])

{

    int i, j = 0;

    for (i = 0; i < argc ; i++)

           j = j + atoi ( argv[i]);

    printf ("%d", j);

}

What will be output of following c code?

#include <stdio.h>
int main()

{
    int i;
    for(i=10;i<=15;i++){
         while(i){
             do{
                 printf("%d ",1);
                 if(i>1)
                      continue;
             }while(0);
             break;
         }
    }
    return 0;
}

What will be output of following program ?

#include
int main()

{

int a = 10;
void *p = &a;
int *ptr = p;
printf("%u",*ptr);
return 0;

}

What will be output of following program?


#include <stdio.h>
int main()

{
   void (*p)();
   int (*q)();
   int (*r)();
   p = clrscr;
   q = getch;
   r = puts;
  (*p)();
  (*r)("www.sawaal.com");
  (*q)();
  return 0;
}

The output of the code below is

        #include <stdio.h>
        int *m()
        {
            int *p = 5;
            return p;
        }
        void main()
        {
            int *k = m();
            printf("%d", k);
        }

 What is the output of this C code? 

        #include <stdio.h>
        void m()
        {
            printf("hi");
        }
        void main()
        {
            m();
        }

The output of the code below is

       #include <stdio.h>
        void main()
        {
            int i = 0, k;
            if ( i == 0 )
                goto label;
                for ( k = 0;k < 3; k++ )
                {
                    printf( "hin" );
                    label: k = printf( "%03d", i );
                }
         }

How many times i value is checked in the below code?

       #include <stdio.h>
        int main()
        {
            int i = 0;
            do {
                i++;
                printf( "In while loopn" );
            } while (i < 3);
        }

What is the output of this C code?

   #include <stdio.h>
    int main()
    {
        int a = 1, b = 1;
        switch (a)
        {
        case a*b:
            printf("yes ");
        case a-b:
            printf("non");
            break;
        }
    }