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Q:

If log 2 = 0.3010 and log 3 = 0.4771, the values of log₅ 512 is

A) 2.875	B) 3.875
C) 4.875	D) 5.875

Answer & Explanation Answer: B) 3.875

Explanation:

ANS: log₅512 = log512/log5 = $\frac{\log 2^{9}}{\log (10 / 2)}$ = $\frac{9 \log 2}{\log 10 - \log 2}$ = $\frac{9 * 0.3010}{1 - 0.3010}$ =2.709/0.699 =2709/699 =3.876

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

How much does a watch lose per day, if its hands coincide ever 64 minutes?

A) 32 8/11	B) 33 8/11
C) 34 8/11	D) 35 8/11

Answer & Explanation Answer: A) 32 8/11

Explanation:

55min spaces are covered in 60min

60 min. spaces are covered in (60/55 x 60) min= 65+5/11 min.

loss in 64min=(65+5/11)- 64 =16/11

Loss in 24 hrs (16/11 x 1/64 x 24 x 60) min= 32 8/11.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?

A) 3 cm	B) 4 cm
C) 6 cm	D) 8 cm

Answer & Explanation Answer: C) 6 cm

Explanation:

Let height =x Then, base =2x

2x * x = 72

=>x=6

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?

A) 10cm	B) 20cm
C) 30cm	D) 40cm

Answer & Explanation Answer: B) 20cm

Explanation:

Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is $2 x^{2}$

after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)= $2 x^{2} + 5 x - 25$

since new area is 75 units greater than original area thus
$2 x^{2} + 75 = 2 x + 5 x - 25$
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?

A) 56m	B) 65m
C) 34m	D) 36m

Answer & Explanation Answer: A) 56m

Explanation:

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

Hence number of poles required = 280 / 5 = 56

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is

A) 64%	B) 74%
C) 84%	D) 94%

Answer & Explanation Answer: A) 64%

Explanation:

Area of the sheet = $(20 \times 30) c m^{2}$

Area used for typing = $[(20 - 4) \times (30 - 6)] c m^{2}$

required % = $\frac{384}{600} \times 100$ =64%

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

A) 315	B) 385
C) 415	D) 485

Answer & Explanation Answer: A) 315

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, $[x - (700 - x)] = \frac{1}{5} [\frac{x + (700 - x)}{2}]$

$\Rightarrow 2 x - 700 = 70$

$\Rightarrow x = 385$

So, the two parts are 385 and 315.

Hence, Area of the smaller = 315 hectares

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?

A) 44ft	B) 88ft
C) 22ft	D) 11ft

Answer & Explanation Answer: B) 88ft

Explanation:

Given that length and area, so we can find the breadth.

Length x Breadth = Area

=> 20 x Breadth = 680

=> Breadth = 34 feet

Area to be fenced = 2B + L = 2 (34) + 20 = 88 feet

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

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