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Q:

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is

A) 200m	B) 300m
C) 400m	D) 100m

Answer & Explanation Answer: A) 200m

Explanation:

Let the triangle and parallelogram have common base b,

let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then

Area of triangle = $\frac{1}{2} \times b \times h 1$

Area of rectangle = b*h2

As per Given,

$\frac{1}{2} * b * h 1 = b * h 2$

$\frac{1}{2} * b * h 1 = b * 100$

h1=200

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A rectangular parking space is marked out by painting three of its sides.If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet?

A) 126sq.ft	B) 120sq.ft
C) 130sq.ft	D) 135sq.ft

Answer & Explanation Answer: A) 126sq.ft

Explanation:

Let l = 9 ft.

Then l + 2b = 37

=> 2b = 37 – l = 37 – 9 = 28

b = 28/2 = 14 ft.

Area = lb = 9 × 14 = 126 sq. ft.

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Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20	B) 200
C) 300	D) 400

Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40] * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters.

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Filed Under: Area
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Q:

The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?

A) 47500	B) 37500
C) 57500	D) 77500

Answer & Explanation Answer: B) 37500

Explanation:

Let length = x meters, then breadth = 0.6x

Given that perimeter = 800 meters

=> 2[ x + 0.6x] = 800

=> x = 250 m

Length = 250m and breadth = 0.6 x 250 = 150m

Area = 250 x 150 = 37500 sq.m

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Q:

The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?

A) 20 m	B) 30 m
C) 40 m	D) 50 m

Answer & Explanation Answer: A) 20 m

Explanation:

Let breadth=x meters. Then, Length = $\frac{115 x}{100}$ meters

Given that, $x \times \frac{115 x}{100} = 460$

=> x = 20

Breadth = 20

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

A) Tuesday	B) Wednesday
C) Sunday	D) Friday

Answer & Explanation Answer: C) Sunday

Explanation:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005.

So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

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Filed Under: Calendar

Q:

A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.

A) 50 km/hr	B) 60 km/hr
C) 65 km/hr	D) 70 km/hr

Answer & Explanation Answer: B) 60 km/hr

Explanation:

We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.

Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km

New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph

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Filed Under: Time and Distance
Exam Prep: GRE

Q:

Jack takes 20 minutes to jog around the race course one time, and 25 minutes to jog around a second time. What is his average speed in miles per hour for the whole jog if the course is 3 miles long?

A) 6	B) 8
C) 9	D) 10

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