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Q:

The length of a rectangle is 12 cm. What is the width if the area is 72 cm ?

A) 6cm	B) 5cm
C) 3cm	D) 4cm

Answer & Explanation Answer: A) 6cm

Explanation:

A=lb

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Q:

The area of a rectangle is 80 cm.If its length is 16 cm, what is its width?

A) 5cm	B) 10cm
C) 15cm	D) 20cm

Answer & Explanation Answer: A) 5cm

Explanation:

A=LB

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Q:

The length of a rectangular plot is 20 meters more than its breadth. If the cost of fencing the plot @ 26.50 per meter is Rs. 5300. What is the length of the plot in meter?

A) 40m	B) 50m
C) 60m	D) 10m

Answer & Explanation Answer: C) 60m

Explanation:

let breadth = x then length = x+20

perimeter = 5300/26.50 = 200m

2(x+20+x) =200 => 4x+40 =200

x = 40 and length = 40+20 = 60m

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Q:

A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?

A) 65m	B) 45m
C) 55m	D) 56m

Answer & Explanation Answer: D) 56m

Explanation:

perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m

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Q:

If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

A) a	B) a>b
C) a=b	D) none

Answer & Explanation Answer: B) a>b

Explanation:

Take a square of side 4cm and a rectangle having l=6cm and b=2cm

then perimeter of square = perimeter of rectangle

area of square = 16 sq.cm

area of rectangle = 12 sq.cm

Hence a >b

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Q:

A square and rectangle have equal areas. If their perimeters are p and q respectively. Then

A) p	B) p>q
C) p=q	D) none of these

Answer & Explanation Answer: A) p
Explanation:

square and a rectangle with equal areas will satisfy the
relation p < q

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Q:

A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?

A) 10ft	B) 20ft
C) 30ft	D) 40ft

Answer & Explanation Answer: B) 20ft

Explanation:

let the radius of the pool be Rft

Radius of the pool including the wall = (R+4)ft

Area of the concrete wall = $π [{(R + 4)}^{2} - R^{2}]$ = $π [(R + 4 + R) (R + 4 - R)] = 8 π (R + 2)$ sq feet

=> 8 $π (R + 2) = \frac{11}{25} {πR}^{2} = > 11 R^{2} = 200 (R + 2)$

Radius of the pool R = 20ft

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Q:

Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is

A) 22m/s	B) 33m/s
C) 44m/s	D) 55m/s

Answer & Explanation Answer: A) 22m/s

Explanation:

let each wheel make x revolutions per sec. Then $[(2 π * \frac{7}{2} * x) + (2 π * 7 * x)] * 10 = 1980$ $(2 * \frac{22}{7} * \frac{7}{2} * x) + (2 * \frac{22}{7} * \frac{7}{2} * x) = 198$

$66 x = 198$

distance moved by smaller wheel in 3 revolutions

= $2 * \frac{22}{7} * \frac{7}{2} * 3 = 66 c m$

speed of smaller wheel = $\frac{66}{3}$ m/s = 22m/s

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