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Q:

In an NGO the daily average wages of 20 illiterate employees is decreased from Rs.25 to Rs.10, thus the average salary of all the literate and illiterate employees is decreased Rs.10 per day. The No. of educated employees working in the NGO is :

A) 15	B) 20
C) 10	D) Data Insufficient

Answer & Explanation Answer: C) 10

Explanation:

Total employees = $\frac{(25 - 10) \times 20}{10} = 30$

Hence number of educated employees = 30-20 = 10

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Filed Under: Average

Q:

The average of 26,29,n,35 and 43 lies between 25 and 35. If n is always an integer and greater than the average of the given integers then the value of n is :

A) 33	B) 34
C) 33	D) None of these

Answer & Explanation Answer: C) 33
Explanation:

Average of 26,29,35 and 43 is 33.25 . Also the average of 26 , 29, n, 35 and 43 lies between 25 and 35 i.e,

$25 < \frac{26 + 29 + n + 35 + 43}{5} < 35$

=> 125 < 26+29+n+35+43 < 175

=> 125 < 133 + n < 175

=> n < 42

Since the value of n is an integer and greater than 33.25 then 33 < n < 42 for every integer n.

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Filed Under: Average

Q:

8 years ago there were 5 members in the Arthur's family and then the average age of the family was 36 years. Mean while Arthur got married and gave birth to a child. Still the average age of his family is same now. What is the age of his wife at the time of his child's birth was.If the difference between the age of her child and herself was 26 years.

A) 25 years	B) 26 years
C) 20 years	D) can't be determined

Answer & Explanation Answer: B) 26 years

Explanation:

Since we know that the difference b/w the age of any two persons remains always constant, while the ratio of their ages gets changed as the time changes.

so, if the age of his child be x (presently)

Then the age of wife be x + 26 (presently)

Thus the total age = x + ( x + 26) = 32 [ $∵$ 252-220 =32]

=> x = 3

Therefore, The age of her child is 3 years and her self is 29 years. Hence her age at the time of the birth of her child was 26 years.

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Filed Under: Average

Q:

The average of any 5 consecutive odd natural numbers is k . If two more such numbers , just next to the previous 5 numbers are added , the new average becomes

A) 2(k+1)	B) 2k-3
C) 2k+1	D) k+2

Answer & Explanation Answer: D) k+2

Explanation:

The 5 consecutive odd numbers whose average is k are (k-4), (k-2), k, (k+2), (k+4)

Again the average of (k-4), (k-2), k, (k+2), (k+4), (k+6), (k+8) is (k+2)

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Filed Under: Average

Q:

Amithab's average expenditure for the January to June is Rs. 4200 and he spends Rs.1200 in January and Rs.1500 in july.The average expenditure for the months of febraury to July is:

A) Rs. 4250	B) Rs. 4520
C) Rs. 4060	D) None of these

Answer & Explanation Answer: A) Rs. 4250

Explanation:

Amithab's total expenditure for Jan - June = 4200 x 6 = 25200

Expenditure for Feb - June = 25200-1200 = 24000

Expenditure for the months of Feb - July = 24000 + 1500 =25500

The average expenditure = 25500/6 = 4250

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Filed Under: Average

Q:

123 typists typeed 984 papers in 1/15 hour. The number of papers typed for minute by a average typist is:

A) 1	B) 2
C) 3	D) 5

Answer & Explanation Answer: B) 2

Explanation:

Use unitary method:

In $\inline \frac{1}{15}$ hours, 123 typists can type 984 paper

In 1 minute, 123 typists can type $\inline \frac{984}{4}$ = 246 papers

In 1 minute, 1 typist can type $\inline \frac{246}{123}$ =2 papers [ Hint $\inline \frac{1}{15}$ hours = 4 minutes]

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Filed Under: Average

Q:

There are two containers, the first one contains 1 litre pure water and the second one contains 1 litre pure milk.Now 5 cups of water from the first container is taken out is mixed well in the second container. Then, 5 cups of this mixture is taken out and is mixed in the first container. Let A denote the proportion of milk in the first container and B denote the proportion of water in the second container then:

A) A	B) A=B
C) A>B	D) can't be determined

Answer & Explanation Answer: B) A=B

Explanation:

Here the ratio of mixtures( i.e milk , water) doesnot matter. But the important point is that whether the total amount ( either pure or mixture ) being transferred is equal or not.Since the total amount ( i.e 5 cups) being transferred from each one to another , hence A =B.

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Filed Under: Ratios and Proportions

Q:

Alloy A contains 40% gold and 60% silver. Alloy B contains 35% gold and 40% silver and 25% copper. Alloys A and B are mixed in the ratio of 1:4 .What is the ratio of gold and silver in the newly formed alloy is?

A) 20% and 30%	B) 36% and 44%
C) 25% and 35%	D) 49% and 36%

Answer & Explanation Answer: B) 36% and 44%

Explanation:

Assume the weight of alloy a is 100 kg

Therefore, The weight of alloy B is 400kg

Gold silver copper

A 40kg 60kg 0kg

B 140kg 160kg 100kg

total 180kg 220kg 100kg

Therefore, Ratio of gold and silver in new alloy = $\frac{180}{500} : \frac{200}{500}$ = 36% :44%

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Filed Under: Ratios and Proportions

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