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Q:

In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:

A) 18 m	B) 20 m
C) 27m	D) 9 m

Answer & Explanation Answer: B) 20 m

Explanation:

A : B = 100 : 90.

A : C = 100 : 72.

B:C = B/A*A/C = 90/100*100/72 = 90/72

When B runs 90 m, C runs 72 m.

When B runs 100 m, C runs (72/90*100)m = 80m

B can give C 20 m.

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Filed Under: Races and Games

Q:

In a 300 m race, A beats B by 22.5 m or 6 seconds. B's time over the course is:

A) 86 sec	B) 80 sec
C) 76 sec	D) None of these

Answer & Explanation Answer: B) 80 sec

Explanation:

B runs 45/2mts in 6 sec

B covers 300m in (6*2/45*300)sec =80 sec

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Filed Under: Races and Games

Q:

In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:

A) 40 sec	B) 47 sec
C) 33 sec	D) None of these

Answer & Explanation Answer: C) 33 sec

Explanation:

B runs 35 m in 7 sec.

B covers 200 m in (7/35*200) = 40sec

B's time over the course = 40 sec.

A's time over the course (40 - 7) sec = 33 sec.

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Filed Under: Races and Games

Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A) 3years	B) 2years
C) 4years	D) 6years

Answer & Explanation Answer: B) 2years

Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000*(1+7/100)^n=34347

n= 2 years

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What is the difference between the compound interests on Rs. 5000 for $1 \frac{1}{2}$ years at 4% per annum compounded yearly and half-yearly?

A) Rs.3.06	B) Rs.2.04
C) Rs.3.65	D) Rs.5.40

Answer & Explanation Answer: B) Rs.2.04

Explanation:

C.I. when interest compounded yearly

$R s . [5000 * (1 + \frac{4}{100}) * (1 + \frac{\frac{1}{2} * 4}{100})]$

$R s . [5000 * \frac{26}{25} * \frac{51}{50}]$

=Rs.5034

C.I. when interest iscompounded half-yearly

$R s . [5000 * {(1 + \frac{2}{100})}^{3}]$

= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Output of the Program :

main()

{

int i = 1;

while (i <= 5)

{

printf( "%d", i );

if (i > 2) goto here;

i++;

}

fun()

{

here : printf( "PP" );

}

A) 1	B) 2
C) Compilation error	D) Exception occurs

Answer & Explanation Answer: C) Compilation error

Explanation:

Compiler error: Undefined label 'here' in function main

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Filed Under: Programming

Q:

What is the rate of simple interest?
I. The total interest earned was Rs. 4000.
II. The sum was invested for 4 years.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are not sufficient to answer

Answer & Explanation Answer: D) Both I and II are not sufficient to answer

Explanation:

We know that, R = (100 x S.I) / (P x T)

Now I gives, S.I = Rs. 4000.

II gives, T = 4 years.

But, P is unknown. So, we cannot find R.

So, given data is insufficient to get R.

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A sum at simple interest at $13 \frac{1}{2}$ % per annum amounts to Rs. 2502.50 after 4 years. Find the sum

A) Rs.1625	B) Rs1525
C) Rs.1425	D) Rs.1325

Answer & Explanation Answer: A) Rs.1625

Explanation:

Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50

Amount =Rs [ x + (27x/50)] = Rs.77x/50

=> 77X/50 = 2502.50

=>X= (2502.50 * 50)/77 = 1625

Hence Sum = Rs.1625

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

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