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Q:

A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?

A) 56m	B) 65m
C) 34m	D) 36m

Answer & Explanation Answer: A) 56m

Explanation:

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

Hence number of poles required = 280 / 5 = 56

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Q:

The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.

A) Rs.15500	B) Rs.16500
C) Rs.17500	D) Rs.18500

Answer & Explanation Answer: B) Rs.16500

Explanation:

Area = 5.5 × 3.75 sq. metre.

Cost for 1 sq. metre. = Rs. 800

Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500

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Q:

A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is

A) 64%	B) 74%
C) 84%	D) 94%

Answer & Explanation Answer: A) 64%

Explanation:

Area of the sheet = $(20 \times 30) c m^{2}$

Area used for typing = $[(20 - 4) \times (30 - 6)] c m^{2}$

required % = $\frac{384}{600} \times 100$ =64%

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Q:

2 metres broad pathway is to be constructed around a rectangular plot on the inside. The area of the plots is 96 sq.m. The rate of construction is Rs. 50 per square metre. Find the total cost of the construction?

A) 20	B) 30
C) 40	D) data is inadequate

Answer & Explanation Answer: D) data is inadequate

Explanation:

Given lb =96

Area of pathway = [(l-4)(b-4)-lb] = 16-4(l+b)

Which cannot be determined. so, data is inadequate.

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Q:

A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

A) 315	B) 385
C) 415	D) 485

Answer & Explanation Answer: A) 315

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, $[x - (700 - x)] = \frac{1}{5} [\frac{x + (700 - x)}{2}]$

$\Rightarrow 2 x - 700 = 70$

$\Rightarrow x = 385$

So, the two parts are 385 and 315.

Hence, Area of the smaller = 315 hectares

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Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?

A) 44ft	B) 88ft
C) 22ft	D) 11ft

Answer & Explanation Answer: B) 88ft

Explanation:

Given that length and area, so we can find the breadth.

Length x Breadth = Area

=> 20 x Breadth = 680

=> Breadth = 34 feet

Area to be fenced = 2B + L = 2 (34) + 20 = 88 feet

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Q:

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is

A) 200m	B) 300m
C) 400m	D) 100m

Answer & Explanation Answer: A) 200m

Explanation:

Let the triangle and parallelogram have common base b,

let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then

Area of triangle = $\frac{1}{2} \times b \times h 1$

Area of rectangle = b*h2

As per Given,

$\frac{1}{2} * b * h 1 = b * h 2$

$\frac{1}{2} * b * h 1 = b * 100$

h1=200

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Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20	B) 200
C) 300	D) 400

Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40] * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters.

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