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Q:

What was the day of the week on 28th May, 2006?

A) Sunday	B) Friday
C) Wednesday	D) Tuesday

Answer & Explanation Answer: A) Sunday

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days

(31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd days.

Given day is Sunday

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Filed Under: Calendar

Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A) Monday	B) Friday
C) Sunday	D) Tuesday

Answer & Explanation Answer: B) Friday

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

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Filed Under: Calendar

Q:

The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of

A) 45%	B) 40%
C) 35%	D) 32.5%

Answer & Explanation Answer: B) 40%

Explanation:

Let the original price of the cycle be 100. After the first reduction the price will be 75.

This new price is then reduced by 20% = 0.8 x 75 = 60

60 represents a reduction of 40 percent on the original.

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Filed Under: Percentage
Exam Prep: GRE

Q:

A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.

A) 50 km/hr	B) 60 km/hr
C) 65 km/hr	D) 70 km/hr

Answer & Explanation Answer: B) 60 km/hr

Explanation:

We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.

Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km

New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph

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Filed Under: Time and Distance
Exam Prep: GRE

Q:

Jack takes 20 minutes to jog around the race course one time, and 25 minutes to jog around a second time. What is his average speed in miles per hour for the whole jog if the course is 3 miles long?

A) 6	B) 8
C) 9	D) 10

Answer & Explanation Answer: B) 8

Explanation:

Average speed = total distance / total time

Total distance covered = 6 miles; total time = 45 minutes = 0.75 hours

Average speed = 6/ 0.75 = 8 miles/hour

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Filed Under: Height and Distance
Exam Prep: GRE

Q:

The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is

A) 720	B) 180
C) 75	D) 65

Answer & Explanation Answer: C) 75

Explanation:

The hour hand moves from pointing to 12 to pointing to half way between 2 and 3. The angle covered between each hour marking on the clock is 360/12 = 30. Since the hand has covered 2.5 of these divisions the angle moved through is 75.

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Filed Under: Time and Distance
Exam Prep: GRE

Q:

x = y - (50/y), where x and y are both > 0

If the value of y is doubled in the equation above, the value of x will

A) decrease	B) stay the same
C) increase four fold	D) increase to more than double

Answer & Explanation Answer: D) increase to more than double

Explanation:

The best approach is to pick a number that satisfies the rules that x and y are greater than 0. So for example you could choose 25 for y.

The value of x before doubling is then 25 - 50/25 = 23

The value after doubling y will be 50 - 50/50 = 49, which is more than double.

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Filed Under: Numbers
Exam Prep: GRE

Q:

The number 0.127 is how much greater than 1/8 ?

A) 1/100	B) 1/1500
C) 1/2	D) 1/500

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