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Q:

Find the annual income derived from Rs. 2500, 8% stock at 106?

A) 100	B) 200
C) 150	D) 250

Answer & Explanation Answer: B) 200

Explanation:

Income from Rs. 100 stock = Rs. 8.

Income from Rs. 2500 stock = $R s (\frac{8}{100} * 2500)$ = Rs. 200.

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Q:

Find the cost of Rs. 6400, 10% stock at 15 discount?

A) 2000	B) 5440
C) 6000	D) 5140

Answer & Explanation Answer: B) 5440

Explanation:

Cost of Rs. 100 stock = Rs. (100-15)

Cost of Rs. 6400 stock = $R s . \frac{85}{100} * 6400$ = Rs. 5440.

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Q:

Find the cost of Rs. 4500, 8.5% stock at 4 premium?

A) 1400	B) 5000
C) 4000	D) 4680

Answer & Explanation Answer: D) 4680

Explanation:

Cost of Rs. 100 stock = Rs. (100+4) = Rs.104

Cost of Rs. 4500 stock = $R s . \frac{104}{100} \times 4500$ = Rs. 4680

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Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is $7 C_{5}$ .

So,required probability = $7 C_{5}$ / $10 C_{5}$ = 1/12.

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Q:

A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: A) 5/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is $3 C_{1} * 7 C_{4}$

So,required probability = $3 C_{1} * 7 C_{4}$ / $10 C_{5}$ = 5/12.

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Q:

A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A) 551/15134	B) 1/2
C) 552/15379	D) 1/9

Answer & Explanation Answer: A) 551/15134

Explanation:

Total number of elementary events = $50 C_{5}$
Given,third ticket =30

=> first and second should come from tickets numbered 1 to 29 = $29 C_{2}$ ways and remaining two in $20 C_{2}$ ways.

Therfore,favourable number of events = $29 C_{2} * 20 C_{2}$

Hence,required probability = $29 C_{2} * 20 C_{2}$ $/ 50 C_{5}$ =551 / 15134

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Q:

The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being 1/4%, is:

A) 108.25	B) 112.20
C) 124.75	D) 125.25

Answer & Explanation Answer: C) 124.75

Explanation:

For an income of Rs. 756, investment = Rs. 9000.

For an income of $R s . \frac{21}{2}$ , investment = $R s . \frac{9000}{756} \times \frac{21}{2}$ = Rs. 125.

For a Rs. 100 stock, investment = Rs. 125.

Market value of Rs. 100 stock = $R s . (125 - \frac{1}{4})$ = Rs. 124.75

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Q:

A 12% stock yielding 10% is quoted at:

A) 67	B) 110
C) 112	D) 120

Answer & Explanation Answer: D) 120

Explanation:

To earn Rs. 10, money invested = Rs. 100.

To earn Rs. 12, money invested = $R s . (\frac{100}{10} * 12)$ = Rs. 120.

Market value of Rs. 100 stock = Rs. 120.

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