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Q:

Which is the Stack used in 8085?

Answer

LIFO (Last In First Out) stack is used in 8085. in this type of Stack the last stored information can be retrieved first.

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Subject: Hardware

Q:

In what way interrupts are classified in 8085?

Answer

in 8085 the interrupts are classified as Hardware and Software interrupts.

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Subject: Hardware

Q:

How many interrupts are there in 8085?

Answer

There are 12 interrupts in 8085.

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Subject: Hardware

Q:

what is the clock frequency for 8085?

Answer

3MHz is the maximum clock frequency for 8085.

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Subject: Hardware

Q:

Can RC circuit be used as clock source for 8085?

Answer

Yes, it can be used, if an accurate clock frequency  is not required. also the component cost is low compared to LC or Crystal.

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Subject: Hardware

Q:

Can 8259 he interfaced with 8085 via the trap pin?

Answer

Yes... so if 8529 gives interrupt then it will be serviced immediately but since INTA pin is left hanging the INSR bit will never be set.. and so whenever my interrupt occurs depending upon priority it will be serviced.. also the ISR address for all interrupts will be same ie 0024H..


Interrupt via trap is nonmaskable, so it will be serviced immediately.

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Subject: Hardware

Q:

A certain factory employed 600 men and 400 women and the average wager was Rs. 25.50 per day, If a woman got Rs. 5 less than a man, then what are their daily wages ?

A) m:25.50 w:27.50 B) m:27.50 w:22.50
C) m:26.50 w:27.50 D) m: 24.50 w:26.50
 
Answer & Explanation Answer: B) m:27.50 w:22.50

Explanation:

Let the daily wage of a man be Rs. x.

Then, daily wage of a woman = Rs. (x - 5).

Now, 600x + 400 (x - 5) = 25.50 * (600 + 400) <=>  1000x = 27500 <=>  x = 27.50.

Man's daily wages = Rs. 27.50; Woman's daily wages = (x - 5) = Rs. 22.50.

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Filed Under: Average

Q:

The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?

A) 76 B) 79
C) 85 D) 87
 
Answer & Explanation Answer: A) 76

Explanation:

Average = total runs / no.of innings = 32 

So, total = Average x no.of innings = 32 x 10 = 320.

 

Now increase in avg = 4runs. So, new avg = 32+4 = 36runs 

Total runs = new avg x new no. of innings = 36 x 11 = 396 

Runs made in the 11th inning = 396 - 320 = 76

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Filed Under: Average