Which Search

Q:

Study the following graph carefully and answer the questions given below:

Distribution of candidates who were enrolled for MBA entrance exam and the candidates (out of those enrolled) who passed the exam in different institutes:

1. What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?

A. 50% B. 62.5% C. 75% D. 80%

2. Which institute has the highest percentage of candidates passed to the candidates enrolled?

A. Q B. R C. V D. T

3. The number of candidates passed from institutes S and P together exceeds the number of candidates enrolled from institutes T and R together by:

A. 228 B. 279 C. 399 D. 407

4. What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?

A. 68% B. 80% C. 74% D. 65%

5. What is the ratio of candidates passed to the candidates enrolled from institute P?

A. 9:11 B. 14:17 C. 6:11 D. 9:17

Answer

1. ANSWER : C

Explanation - Required percentage= $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = $\frac{9 \times 5700}{8 \times 8550} \times 100$ % = 75%

2. ANSWER : B

Explanation - The percentage of candidates passed to candidates enrolled can be determined for each institute as under:

P = $\frac{18 % o f 5700}{22 % o f 8550} \times 100$ % = 54.55%

Q = $\frac{17 % o f 5700}{15 % o f 8550} \times 100$ % = 75.56%

R = $\frac{13 % o f 5700}{10 % o f 8550} \times 100$ % = 86.67%

S = $\frac{16 % o f 5700}{17 % o f 8550} \times 100$ % = 62.75%

T = $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = 75%

V= $\frac{15 % o f 5700}{12 % o f 8550} \times 100$ % = 83.33%

X= $\frac{12 % o f 5700}{16 % o f 8550} \times 100$ % = 50%

Highest of these is 86.67% corresponding to institute R.

3. ANSWER : C

Explanation - Required difference = [(16% + 18%) of 5700] - [(8% + 10%) of 8550]

= [(34% of 5700) - (18% of 8550)]

= (1938 - 1539)

= 399

4. ANSWER : B

Explanation - Candidates passed from institutes Q and R together = [(13% + 17%) of 5700] = 30% of 57000.

Candidates enrolled from institutes Q and R together = [(15% + 10%) of 8550] = 25% of 8550.

Required Percentage = $\frac{30 % o f 5700}{25 % o f 8550} \times 100$ % = 80%

5. ANSWER : C

Explanation - Required ratio = $\frac{18 % o f 5700}{22 % o f 8550}$ = 6/11

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Pie Charts

Q:

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Table Charts

Q:

Study the following table and answer the questions based on it. Expenditures of a Company (in Pesetas) per Annum Over the given Years.

1. What is the average amount of interest per year which the company had to pay during this period?

A. 32.43 B. 33.72 C. 34.18 D. 36.66

2. The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?

A. 0.1% B. 0.5% C. 1.0% D. 1.25 %

3. Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?

A. 62% B. 66% C. 69% D. 71%

4. The total expenditure of the company over these items during the year 2000 is?

A. 544.44 B. 501.11 C. 446.46 D. 478.87

5. The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?

A. 4 : 7 B. 10 : 13 C. 15 : 18 D. 5 : 8

The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

The total expenditure of the company over these items during the year 2000 is? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

0.1%

What is the average amount of interest per year which the company had to pay during this period? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

Answer

1. ANSWER : D

Explanation -

Average amount of interest paid by the company during the given period

= $R s . \frac{23.4 + 32.5 + 41.6 + 36.4 + 49.4}{5} l a k h s = R s . \frac{183.3}{5} l a k h s$

= Rs. 36.66 lakhs

2. ANSWER : C

Explanation -

Required Percentage = $\frac{3.00 + 2.52 + 3.84 + 3.68 + 3.96}{288 + 342 + 324 + 336 + 420} \times 100$ %

= $\frac{17}{1710} \times 100$ % $\approx$ 1%

3. ANSWER: C

Explanation -

Required Percentage = $\frac{288 + 98 + 3.00 + 23.4 + 83}{420 + 142 + 3.96 + 49.4 + 98} \times 100$

= $\frac{495.4}{713.36} \times 100$ $\approx$ 69.45%

4. ANSWER: A

Explanation - Total expenditure of the Company during 2000 = (324 + 101 + 3.84 + 41.6 + 74) lakhs = 544.44 lakhs

5. ANSWER : B

Explanation -

Required ratio = $\frac{83 + 108 + 74 + 88 + 98}{98 + 112 + 101 + 133 + 142}$

= $\frac{451}{586}$

= $\frac{1}{1.3} = \frac{10}{13}$

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Table Charts

Q:

Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies ove the Years (Number in Thousands)

1. What is the difference between the number of vehicles manufactured by Company Y in 2000 and 2001 ?

A. 50000 B. 42000 C. 33000 D. 21000

2. What is the difference between the total productions of the two Companies in the given years ?

A. 19000 B. 22000 C. 26000 D. 28000

3. What is the average numbers of vehicles manufactured by Company X over the given period ? (rounded off to nearest integer)

A. 119333 B. 113666 C. 112778 D. 111223

4. In which of the following years, the difference between the productions of Companies X and Y was the maximum among the given years ?

A. 1997 B. 1998 C. 1999 D. 2000

5. The production of Company Y in 2000 was approximately what percent of the production of Company X in the same year ?

A. 173 B. 164 C. 132 D. 97

Answer

1. ANSWERS : D

Explanation- Required difference = (128000 - 107000) = 21000.

2. ANSWERS : C

Explanation- From the line-graph it is clear that the productions of Company X in the years 1997, 1998, 1999, 2000, 2001 and 2002 are 119000, 99000, 141000, 78000, 120000 and 159000 and those of Company Y are 139000, 120000,100000, 128000, 107000 and 148000 respectively.

Total production of Company X from 1997 to 2002

= 119000 + 99000 + 141000 + 78000 + 120000 + 159000

= 716000.

and total production of Company Y from 1997 to 2002

= 139000 + 120000 + 100000 + 128000 + 107000 + 148000

= 742000.

Difference = (742000 - 716000) = 26000.

3. ANSWERS : A

Explanation- Average number of vehicles manufactured by Company X

= $\frac{1}{6} \times (119000 + 99000 + 141000 + 78000 + 120000 + 159000)$

= 119333.

4. ANSWERS : D

Explanation- The difference between the productions of Companies X and Y in various years are:

For 1997 (139000 - 119000) = 20000.

For 1998 (120000 - 99000) = 21000.

For 1999 (141000 - 100000) = 41000.

For 2000 (128000 - 78000) = 50000.

For 2001 (120000 - 107000) = 13000.

For 2002 (159000 - 148000) = 11000.

Clearly, maximum difference was in 2000.

5. ANSWERS : B

Explanation - Required percentage= $\frac{128000}{78000} \times 100$ % = 164%

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Line Charts

Q:

Which of the following are acceptable names of an ABAP program?

A. ZQSDABAP
B. YMYFIRSTABAPPROGRAM
C. Z”MyFirst ABAP PROGRAM
D. Z==FIRSTABAPPROGRAM
E. THISISMYFIRSTABAPPROGRAMME

Answer

Answer: A, B, E

The name of an ABAP program can be between 1 and 30 characters long.

The following symbols and signs must not be used in program names:
Period (.), comma (,), space ( ), parentheses (), apostrophe (‘), inverted commas ("), equals sign (=), asterisk
(*), accented characters or German umlauts (à, é, ø, ä, ß, and so on), percentage signs (%), or underscores (_).

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: ABAP

Q:

If you have 10000 records in your file, which method you use in BDC?

Answer

Call transaction is faster than session method. But usually we use session method in real time…because we can transfer large amount of data from internal table to database and if any errors in a session, then process will not complete until session get correct.

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: ABAP

Q:

Refer to the exhibit. Which statement describes DLCI 17?

A: DLCI 17 describes the ISDN circuit between R2 and R3.
B: DLCI 17 describes a PVC on R2. It cannot be used on R3 or R1.
C: DLCI 17 is the Layer 2 address used by R2 to describe a PVCto R3.
D: DLCI 17 describes the dial-up circuit from R2 and R3 to the service provider.

Answer

Answer : C

Explanation:

Virtual circuits (VC)s are identified by DLCIs. DLCI values typically are assigned by the Frame Relay service provider. Frame Relay DLCIs have local significance. A DLCI identifies a VC to the equipment at an endpoint. A DLCI has no significance beyond the single link. Two devices connected by a VC may use a different DLCI value to refer to the same connection.

Virtual circuits (VC)s are identified by DLCIs. DLCI values typically are assigned by the Frame Relay service provider. Frame Relay DLCIs have local significance. A DLCI identifies a VC to the equipment at an endpoint. A DLCI has no significance beyond the single link. Two devices connected by a VC may use a different DLCI value to refer to the same connection. - See more at: https://www.orbitco-ccna-pastquestions.com/CCNA-Past-Questions%3A-WAN.php#sthash.nWKdjylM.dpuf

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: CCNA

Q:

Which two descriptions are correct about characteristics of IPv6 unicast addressing? (Choose two)

A. Global addresses start with 2000::/3.
B. Link-local addresses start with FF00::/10.
C. Link-local addresses start with FE00:/12.
D. There is only one loopback address and it is ::1.

Answer

Answer : A , D

Explanation:

An IPv6 Unicast address identifies a single network interface. The Internet Protocol delivers packets sent to a unicast address to that specific interface.

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: CCNA

Searching for "Which"

Quick Links