and Search

Q:

The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275 , then the other is

A) 279	B) 283
C) 308	D) 318

Answer & Explanation Answer: C) 308

Explanation:

Other number = $(\frac{11 \times 7700}{275})$ = 308

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is

A) 4	B) 6
C) 8	D) 12

Answer & Explanation Answer: A) 4

Explanation:

Let the required numbers be 33a and 33b.

Then 33a +33b= 528 => a+b = 16.

Now, co-primes with sum 16 are (1,15) , (3,13) , (5,11) and (7,9).

Therefore, Required numbers are ( 33 x 1, 33 x 15), (33 x 3, 33 x 13), (33 x 5, 33 x 11), (33 x 7, 33 x 9)

The number of such pairs is 4

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

The ratio of two numbers is 3 : 4 and their H.C.F is 4. Their L.C.M is

A) 12	B) 16
C) 24	D) 48

Answer & Explanation Answer: D) 48

Explanation:

Let the numbers be 3x and 4x . Then their H.C.F = x. So, x=4

Therefore, The numbers are 12 and 16

L.C.M of 12 and 16 = 48

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are

A) 4, 8, 12	B) 5, 10, 15
C) 10, 20, 30	D) 12, 24, 36

Answer & Explanation Answer: D) 12, 24, 36

Explanation:

Let the required numbers be x, 2x, 3x. Then, their H.C.F =x. so, x= 12

Therefore, The numbers are 12, 24, 36

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

The G.C.D of 1.08, 0.36 and 0.9 is

A) 0.03	B) 0.9
C) 0.18	D) 0.108

Answer & Explanation Answer: C) 0.18

Explanation:

Given numbers are 1.08 , 0.36 and 0.90

H.C.F of 108, 36 and 90 is 18 [ $∵$ G.C.D is nothing but H.C.F]

Therefore, H.C.F of given numbers = 0.18

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

The L.C.M of 22, 54, 108, 135 and 198 is

A) 330	B) 1980
C) 5940	D) 11880

Answer & Explanation Answer: C) 5940

Explanation:

22 = 2 x 11

54 = $2 \times 3^{3}$

108 = $2^{2} \times 3^{3}$

135 = $3^{3} \times 5$

198 = $2 \times 3^{2} \times 11$

$∴ L . C . M = 2^{2} \times 3^{3} \times 5 \times 11 = 5940$

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is

A) 180	B) 360
C) 540	D) 1260

Answer & Explanation Answer: A) 180

Explanation:

$4 \times 27 \times 3125 = 2^{2} \times 3^{3} \times 5^{5}$

$8 \times 9 \times 25 \times 7 = 2^{3} \times 3^{2} \times 5^{2} \times 7$

$16 \times 81 \times 5 \times 11 \times 49 = 2^{4} \times 3^{4} \times 5 \times 7^{2} \times 11$

Therefore, H.C.F = $2^{2} \times 3^{2} \times 5$ = 180

$\inline \fn_jvn \therefore$ $\inline \fn_jvn H.C.F =2^{2}\times 3^{2}\times 5=180$

Report Error

View Answer Report Error Discuss

Filed Under: HCF and LCM

Q:

Who had an explosive idea and first patented DYNAMITE?

A) J. R. Gluber	B) A. Nobel
C) G. Fawks	D) W. Bickford

Answer & Explanation Answer: B) A. Nobel

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Inventions

Searching for "and"

Quick Links