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Q:

A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?

A) 10%	B) 20%
C) 30%	D) 40%

Answer & Explanation Answer: C) 30%

Explanation:

let the side of the square be x meters
length of two sides = 2x meters
diagonal = $\sqrt{2 x}$ = 1.414x m

saving on 2x meters = .59x m

saving % = $\frac{0.59 x}{2 x} * 100$ %

= 30% (approx)

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Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800	B) 43800
C) 83800	D) 73800

Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Q:

A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

A) rs.58	B) rs.158
C) rs.258	D) rs.358

Answer & Explanation Answer: C) rs.258

Explanation:

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m

cost of graveling = 344 x (75/100) = Rs. 258

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Q:

A took 15 seconds to cross a rectangular field diagonally walking at the rate of 52 m/min and B took the same time to cross the same field along its sides walking at the rate of 68m/min. The area of the field is?

A) 50	B) 60
C) 70	D) 80

Answer & Explanation Answer: B) 60

Explanation:

length of the diagonal = 52 x (15/60) =13m

sum of length and breadth = 68 x (15/60) = 17m

$(\sqrt{l^{2} + b^{2}}) = 13 o r l + b = 17$

area =lb = 1/2[(2lb)] = 1/2[(l+b)² - (l²+b²)] = 1/2[17² -169]

=1/2 x 120 = 60 sq.m

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Q:

A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?

A) 10ft	B) 20ft
C) 30ft	D) 40ft

Answer & Explanation Answer: B) 20ft

Explanation:

let the radius of the pool be Rft

Radius of the pool including the wall = (R+4)ft

Area of the concrete wall = $π [{(R + 4)}^{2} - R^{2}]$ = $π [(R + 4 + R) (R + 4 - R)] = 8 π (R + 2)$ sq feet

=> 8 $π (R + 2) = \frac{11}{25} {πR}^{2} = > 11 R^{2} = 200 (R + 2)$

Radius of the pool R = 20ft

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Q:

Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is

A) 22m/s	B) 33m/s
C) 44m/s	D) 55m/s

Answer & Explanation Answer: A) 22m/s

Explanation:

let each wheel make x revolutions per sec. Then $[(2 π * \frac{7}{2} * x) + (2 π * 7 * x)] * 10 = 1980$ $(2 * \frac{22}{7} * \frac{7}{2} * x) + (2 * \frac{22}{7} * \frac{7}{2} * x) = 198$

$66 x = 198$

distance moved by smaller wheel in 3 revolutions

= $2 * \frac{22}{7} * \frac{7}{2} * 3 = 66 c m$

speed of smaller wheel = $\frac{66}{3}$ m/s = 22m/s

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Q:

The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is

A) 240	B) 140
C) 40	D) 340

Answer & Explanation Answer: B) 140

Explanation:

distance covered in 1 revolution = $2 πr$ = 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140

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Q:

The ratio of bases of two triangles is x:y and that of their areas is a:b. Then the ratio of their corresponding altitudes wll be

A) ay:bx	B) a:b
C) x:y	D) bx:ay

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