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Q:

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is :

A) 2/9	B) 1/9
C) 8/9	D) 7/9

Answer & Explanation Answer: B) 1/9

Explanation:

One person can select one house out of 3= $3 C_{1}$ ways =3.

Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9.

Therefore, probability that all thre apply for the same house is 1/9

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Filed Under: Probability

Q:

If (i) M is brother of N; (ii) B is brother of N; and (iii) M is brother of D, then which of the following statements is definitely true ?

A) N is brother of B	B) N is brother of D
C) M is brother of B	D) D is brother of M

Answer & Explanation Answer: C) M is brother of B

Explanation:

M is the brother of N and B is the brother of N.

So, M is the brother of B

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Filed Under: Blood Relations

Q:

Find the cost of 96 shares of Rs. 10 each at $\frac{3}{4}$ discount, brokerage being 1/4 per share.

A) 912	B) 921
C) 920	D) 900

Answer & Explanation Answer: A) 912

Explanation:

Cost of 1 share = $R s . [(10 - \frac{3}{4}) + \frac{1}{4}] = R s \frac{19}{2}$

Cost of 96 shares = $R s . (\frac{19}{2} * 96)$ = Rs. 912.

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Filed Under: Stocks and Shares

Q:

Find the annual income derived by investing Rs. 6800 in 10% stock at 136.?

A) 250	B) 1500
C) 500	D) 50

Answer & Explanation Answer: C) 500

Explanation:

By investing Rs. 136, income obtained = Rs. 10.

By investing Rs. 6800, income obtained = $R s . \frac{10}{36} \times 6800$ = Rs. 500.

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Filed Under: Stocks and Shares

Q:

Find the cash realised by selling Rs. 2440, 9.5% stock at 4 discount (brokerage 1/4 %)

A) 2000	B) 2298
C) 2290	D) 2289

Answer & Explanation Answer: B) 2298

Explanation:

By selling Rs. 100 stock , cash realised = $R s . [(100 - 4) - \frac{1}{4}] = R s . \frac{383}{4}$

By selling Rs. 2400 stock, cash realised = $R s . (\frac{383}{4} * \frac{1}{100} * 2400)$ = Rs 2298.

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Filed Under: Stocks and Shares

Q:

In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7.

A) 1/2	B) 5/12
C) 7/15	D) 3/12

Answer & Explanation Answer: B) 5/12

Explanation:

Here n(S) = (6 x 6) = 36

Let E = event of getting a total more than 7
= {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}

Therefore,P(E) = n(E)/n(S) = 15/36 = 5/12.

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Filed Under: Probability

Q:

An unbiased die is tossed.Find the probability of getting a multiple of 3.

A) 1/3	B) 1/2
C) 3/4	D) 3/2

Answer & Explanation Answer: A) 1/3

Explanation:

Here S = {1,2,3,4,5,6}

Let E be the event of getting the multiple of 3

Then, E = {3,6}

P(E) = n(E)/n(S) = 2/6 = 1/3

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Filed Under: Probability

Q:

Two unbiased coin are tossed. What is the probability of getting atmost one head?

A) 1/2	B) 3/2
C) 1/6	D) 3/4

Answer & Explanation Answer: D) 3/4

Explanation:

Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4

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Filed Under: Probability

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