Multiple inheritance is a feature in C++ by which one class can be of different types. Say class teaching Assistant is inherited from two classes say teacher and Student.

#include <stdio.h>

int main() {

  int a[5][5], b[5][5], c[5][5], i, j, k, sum = 0, m, n, o, p;

  printf( "\nEnter the row and column of first matrix" );

  scanf( "%d %d", &m, &n );

  printf( "\nEnter the row and column of second matrix" );

  scanf( "%d %d", &o, &p );

  if(n!=o) {

      printf( "Matrix mutiplication is not possible" );

      printf( "\nColumn of first matrix must be same as row of second matrix" );

  }

  else {

      printf( "\nEnter the First matrix" );

      for( i=0; i<m; i++ )

      for( j=0; j<n; j++ )

           scanf( "%d", &a[i][j] );

      printf( "\nEnter the Second matrix" );

      for( i=0; i<o; i++ )

      for( j=0; j<p; j++ )

           scanf( "%d", &b[i][j] );

      printf( "\nThe First matrix is\n" );

      for( i=0; i<m; i++ ) {

      printf("\n");

      for( j=0; j<n; j++ ) {

           printf( "%d\t", a[i][j] );

      }

      }

      printf( "\nThe Second matrix is\n" );

      for( i=0; i<o; i++ ) {

      printf("\n");

      for( j=0; j<p; j++ ) {

           printf( "%d\t", b[i][j] );

      }       

      }

      for( i=0; i<m; i++ )

      for( j=0; j<p;j++ )

           c[i][j] = 0;

      for( i=0; i<m; i++ ) { //row of first matrix

      for( j=0; j<p; j++ )  {  //column of second matrix

           sum = 0;

           for( k=0; k<n; k++ )

               sum = sum + a[i][k]*b[k][j];

           c[i][j] = sum;

      }

      }

  }

  printf( "\nThe multiplication of two matrix is\n" );

  for( i=0; i<m; i++ ) {

      printf("\n");

      for( j=0; j<p; j++ ) {

           printf( "%d\t", c[i][j] );

      }

  }

  return 0;

}

 #include<stdio.h>
int main(){
  int r,i,j,k;
  printf("Enter the number range: ");
  scanf("%d",&r);
  for(i=1;i<=r;i++){
      for(j=1;j<=10;j++)
           printf("%d*%d=%d ",i,j,i*j);
      printf("\n");
  }
  return 0;
}

Sample Output:
Enter the number range: 5

1*1=1 1*2=2 1*3=3 1*4=4 1*5=5 1*6=6 1*7=7 1*8=8 1*9=9 1*10=10
2*1=2 2*2=4 2*3=6 2*4=8 2*5=10 2*6=12 2*7=14 2*8=16 2*9=18 2*10=20
3*1=3 3*2=6 3*3=9 3*4=12 3*5=15 3*6=18 3*7=21 3*8=24 3*9=27 3*10=30
4*1=4 4*2=8 4*3=12 4*4=16 4*5=20 4*6=24 4*7=28 4*8=32 4*9=36 4*10=40
5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 5*6=30 5*7=35 5*8=40 5*9=45 5*10=50

Answer : s1 and s2 are equals()

Explanation :