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Q:

One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.

A) 1/3	B) 1/2
C) 1/4	D) 1/6

Answer & Explanation Answer: B) 1/2

Explanation:

Total number of elementary events = 52

There are 26 red cards,out of which one red card can be drawn in $26 C_{1}$ ways =26.

So,required probability = 26/52 = 1/2

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Filed Under: Probability

Q:

I. A. B, C. D, E and F are six members of a family.

II. One couple has parents and their children in the family.

III. A is the son of C and E is the daughter of A.

IV. D is the daughter of F who is the mother of E.

Which of the following pairs is the parents of the couple ?

A) AB	B) BC
C) AF	D) CF

Answer & Explanation Answer: B) BC

Explanation:

E is the daughter of A and F is the mother of E So, A is the father of E and hence the husband of F. Now,

D is the daughter of F So. D and E are the daughters of A and F Also. A is the son of C.

Now, only B remains Thus. B and C are the parents of A.

Clearly. B and C are the parents of the couple

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Filed Under: Blood Relations

Q:

Which of the following is true ?

A) A is brother of F.	B) A is sister of F.
C) D has two grandsons.	D) None of these.

Answer & Explanation Answer: D) None of these.

Explanation:

The sex of A is not known. So. neither (a) nor (b) is definitely true. Clearly, D is the grandmother of A and F.

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Filed Under: Blood Relations

Q:

What is context switching?

Answer

Transferring the control from one process to other process requires saving the state of the old process and loading the saved state for new process. This task is known as context switching.

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Subject: Operating Systems

Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is $7 C_{5}$ .

So,required probability = $7 C_{5}$ / $10 C_{5}$ = 1/12.

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Q:

A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: A) 5/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is $3 C_{1} * 7 C_{4}$

So,required probability = $3 C_{1} * 7 C_{4}$ / $10 C_{5}$ = 5/12.

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Q:

A is the brother of B. B is the brother of C. D is the father of A. Based on these three statements, which of the following statements cannot be definitely true ?

A) B is the brother of A.	B) B is the son of D.
C) A is the brother of C.	D) C is the brother of A.

Answer & Explanation Answer: D) C is the brother of A.

Explanation:

A is the brother of B and B is the brother of C. So, C may be the brother or sister of A.

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Filed Under: Blood Relations

Q:

What are the different types of Real-Time Scheduling?

Answer

Hard real-time systems required to complete a critical task within a guaranteed amount of time.
Soft real-time computing requires that critical processes receive priority over less fortunate ones.

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Subject: Operating Systems

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