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Q:

A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets ?

A) 40%	B) 45%
C) 50%	D) 55%

Answer & Explanation Answer: C) 50%

Explanation:

Number of runs made by running = 120 - (3 x 4 + 8 x 6) = 120 - (60) = 60

Required percentage = [(60/120)*100] % = 50%

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Q:

Entry fee in an exhibition was Rs. 1. Later, this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is :

A) 20 %	B) 40 %
C) 60 %	D) 80 %

Answer & Explanation Answer: C) 60 %

Explanation:

Let the total original sale be Rs. 100. Then, original number of visitors = 100.

New number of visitors = 120/0.75 = 160.

Increase % = 60 %.

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Q:

A man spends 35% of his income on food, 25% on children's education and 80% of the remaining on house rent. What percent of his income he is left with ?

A) 6 %	B) 8 %
C) 10 %	D) 12 %

Answer & Explanation Answer: B) 8 %

Explanation:

Let the total income be x.

Then, income left = (100 - 80)% of [100 - (35 + 25)] % of x = 20% of 40% of x = [(20/100) * (40/100) * 100] % of x = 8 % of x.

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Q:

If A's height is 40% less than that of B, how much percent B's height is more than that of A?

A) 66.66%	B) 76.66%
C) 96.66%	D) 86.66%

Answer & Explanation Answer: A) 66.66%

Explanation:

Excess of B's height over A's = [(40/(100 - 40)] x 100% = 66.66%

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Q:

In a hoel, 60% had vegetarian lunch while 30% had non-vegetaian lunch and 15% had both types of lunch. If 96 people were present, how many did not eat either type of lunch ?

A) 24	B) 30
C) 36	D) 42

Answer & Explanation Answer: A) 24

Explanation:

n (A) = (60/100 * 96) = 288/5, n (B) = (30/100 * 96) = 144/5, n (A ∩ B) = (15/100 * 96) = 72/5.

n(A ∪ B) = n (A) + n (B) - n (A ∩ B) = 72.

So, people who had either or both types of lunch = 72.

Hence, people who had neither type of lunch = (96 - 72)= 24.

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Q:

405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: A) 9

Explanation:

Let the total number of children be x.

Then, x * (20% of x) = 405

=> x * 20x/100 = 405

$\frac{1}{5} x^{2}$ = 405

=> x=45

Number of sweets received by each child = 20% of 45 = 9.

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Q:

The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is :

A) 60	B) 70
C) 80	D) 90

Answer & Explanation Answer: A) 60

Explanation:

We have : x + (x% of 150 )= 150

=> x+(x/100)*150] = 150

=> $\frac{5}{2} x = 150$

=> x = (150*2)/5 = 60

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Q:

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was :

A) 10000	B) 12000
C) 14000	D) 16000

Answer & Explanation Answer: B) 12000

Explanation:

Purchase price = $R s . [\frac{8748}{{^{(1 - \frac{10}{100})}}^{3}}]$ = Rs. [8748 * (10/9) * (10/9 )* (10/9)] = Rs.12000

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