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Q:

What annual payment will discharge a debt of Rs.7620 due in 3years at $16 \frac{2}{3}$ % per annum interest?

A) 5430	B) 4430
C) 3430	D) 2430

Answer & Explanation Answer: C) 3430

Explanation:

Let each installment be Rs.x. Then,

(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.

$[\frac{x}{(1 + \frac{50}{3 x 100})}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{2}}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{3}}] = 7620$

$\frac{6 x}{7} + \frac{36 x}{49} + \frac{216 x}{343} = 7620$

$294 x + 252 x + 216 x = 7620 x 343$

=> x = 3430

Amount of each installment = Rs.3430

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If the compound interest on a certain sum at $16 \frac{2}{3}$ % to 3 years is Rs.1270, find the simple interest on the same sum at the same rate and f or the same period.

A) 1080	B) 1090
C) 1180	D) 1109

Answer & Explanation Answer: A) 1080

Explanation:

Let the sum be Rs. x. Then,

$C . I = [x * {(\frac{50}{300 * 100})}^{3} - x] = (\frac{343 x}{216} - x) = \frac{127 x}{216}$

$\Leftrightarrow \frac{127 x}{216} = 1270$

$x = 2160$

Thus, the sum is Rs. 2160

$S . I = R s . [2160 * \frac{50}{3} * 3 * \frac{1}{100}] = R s 1080$

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The value of $(\frac{1}{\log_{3} 60} + \frac{1}{\log_{4} 60} + \frac{1}{\log_{5} 60}) i s$

A) 0	B) 1
C) 5	D) 60

Answer & Explanation Answer: B) 1

Explanation:

=> $\log_{60} (3 * 4 * 5)$

=> $\log_{60} (60)$

= 1

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

$i f \log \frac{a}{b} + \log \frac{b}{a} = \log (a + b), t h e n$

A) a + b = 1	B) a - b = 1
C) a = b	D) ab=1

Answer & Explanation Answer: A) a + b = 1

Explanation:

$i f \log \frac{a}{b} + \log \frac{b}{a} = \log (a + b), t h e n$

$\log (a + b) = \log (\frac{a}{b} \times \frac{b}{a}) = \log 1$

so, a+b=1

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

In a race, the odd favour of cars P,Q,R,S are 1:3, 1:4, 1:5 and 1:6 respectively. Find the probability that one of them wins the race.

A) 319/420	B) 27/111
C) 114/121	D) 231/420

Answer & Explanation Answer: A) 319/420

Explanation:

$P (P) = \frac{1}{4}, P (Q) = \frac{1}{5}, P (R) = \frac{1}{6}, P (S) = \frac{1}{7}$
All the events are mutually exclusive hence,

Required probability = P(P)+P(Q)+P(R)+P(S)

$\frac{1}{4} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7}$ = $\frac{319}{420}$

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Filed Under: Probability

Q:

Find the cost of 96 shares of Rs. 10 each at $\frac{3}{4}$ discount, brokerage being 1/4 per share.

A) 912	B) 921
C) 920	D) 900

Answer & Explanation Answer: A) 912

Explanation:

Cost of 1 share = $R s . [(10 - \frac{3}{4}) + \frac{1}{4}] = R s \frac{19}{2}$

Cost of 96 shares = $R s . (\frac{19}{2} * 96)$ = Rs. 912.

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Filed Under: Stocks and Shares

Q:

A man bought 20 shares of Rs. 50 at 5 discount, the rate of dividend being 13 $\frac{1}{2}$ . The rate of interest obtained is:

A) 13%	B) 12
C) 15%	D) 16%

Answer & Explanation Answer: C) 15%

Explanation:

Investment = Rs. [20 x (50 - 5)] = Rs. 900.

Face value = Rs. (50 x 20) = Rs. 1000.

Dividend = $R s . (\frac{27}{2} * \frac{1000}{100}) = R s . 135$

Interest obtained = $\frac{135}{900} * 100$ % = 15%

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Filed Under: Stocks and Shares

Q:

Determine the exact and ordinary simple interest on a 90-day loan of $8000 at $8 \frac{1}{2}$ %

A) 150$	B) $160
C) $170	D) $180

Answer & Explanation Answer: C) $170

Explanation:

Exact interest, I= prt = $8000 × 0.085 × 90/365 = 167.67

Ordinary Interest, I= Prt = $8000 x 0.085 x 90/360 = 170

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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