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Q:

From a total of six men and four ladies a committee of three is to be formed. If Mrs. X is not willing to join the committee in which Mr. Y is a member, whereas Mr.Y is willing to join the committee only if Mrs Z is included, how many such committee are possible?

A) 91	B) 104
C) 109	D) 98

Answer & Explanation Answer: A) 91

Explanation:

We first count the number of committee in which

(i). Mr. Y is a member
(ii). the ones in which he is not

Case (i): As Mr. Y agrees to be in committee only where Mrs. Z is a member.
Now we are left with (6-1) men and (4-2) ladies (Mrs. X is not willing to join).

We can choose 1 more in5+ $2 C_{1}$ =7 ways.

Case (ii): If Mr. Y is not a member then we left with (6+4-1) people.
we can select 3 from 9 in $9 C_{3}$ =84 ways.

Thus, total number of ways is 7+84= 91 ways.

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Filed Under: Permutations and Combinations

Q:

There are five cards lying on the table in one row. Five numbers from among 1 to 100 have to be written on them, one number per card, such that the difference between the numbers on any two adjacent cards is not divisible by 4. The remainder when each of the 5 numbers is divided by 4 is written down on another card (the 6th card) in order. How many sequences can be written down on the 6th card ?

A) 4 x 3^4	B) 3^4
C) 4^3	D) 3 x 4^3

Answer & Explanation Answer: A) 4 x 3^4

Explanation:

The remainder on the first card can be 0,1,2 or 3 i.e 4 possibilities.
The remainder of the number on the next card when divided by 4 can have 3 possible values (except the one occurred earlier).

For each value on the card the remainder can have 3 possible values.

The total number of possible sequences is: 4*3^4

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Filed Under: Permutations and Combinations

Q:

On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?

A) Sunday	B) Monday
C) Tuesday	D) Wednesday

Answer & Explanation Answer: C) Tuesday

Explanation:

The year 1985 is an ordinary year. So, it has 1 odd day.

So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.

But, 19th June,1984 is Monday

S0, 19th June, 1985 is Tuesday.

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Filed Under: Calendar

Q:

Prove that any date in March of a year is the same day of the week corresponding date in November that year.

A) Same day	B) Not same day
C) Next day	D) Previous day

Answer & Explanation Answer: A) Same day

Explanation:

We will show that the number of odd days between last day of February and last day of October is zero. .

March April May June July Aug. Sept. Oct.

31 + 30 + 31 + 30 + 31 + 31 + 30 + 31

= 241 days = 35 weeks = 0 odd day. ,Number of odd days during this period = 0.

Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows

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Filed Under: Calendar

Q:

The calendar of the year 2006 was used before in the year?

A) 1990	B) 1995
C) 2002	D) 2000

Answer & Explanation Answer: B) 1995

Explanation:

Given year 2006, when divided by 4 leaves a remainder of 2.

NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.

So, 2006 - 11 = 1995

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Filed Under: Calendar

Q:

A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?

A) 156	B) 166
C) 176	D) 186

Answer & Explanation Answer: C) 176

Explanation:

Area of the room=(544 * 374)

size of largest square tile= H.C.F of 544 & 374 = 34 cm

Area of 1 tile = (34 x 34) $c m^{2}$

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.

A) Rs.15500	B) Rs.16500
C) Rs.17500	D) Rs.18500

Answer & Explanation Answer: B) Rs.16500

Explanation:

Area = 5.5 × 3.75 sq. metre.

Cost for 1 sq. metre. = Rs. 800

Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is

A) 64%	B) 74%
C) 84%	D) 94%

Answer & Explanation Answer: A) 64%

Explanation:

Area of the sheet = $(20 \times 30) c m^{2}$

Area used for typing = $[(20 - 4) \times (30 - 6)] c m^{2}$

required % = $\frac{384}{600} \times 100$ =64%

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

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