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Q:

A sector of 120 degrees, cut out from a circle, has an area of 66/7 sq cm. Find the radius of the circle.

A) 1cm	B) 2cm
C) 3cm	D) 4cm

Answer & Explanation Answer: C) 3cm

Explanation:

$πr = \frac{66}{7}$

r =3

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Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m	B) 16m
C) 14m	D) 76m

Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts

then, ${πr}^{2} = 9856 \Rightarrow r^{2} = \frac{9856 \times 7}{22} = 3136 \Rightarrow r = 56 m$

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Q:

The dimensions of a room are 10m x 7m x 5m. There are 2 doors and 3 windows in the room. The dimensions of the doors are 1m x 3m. One window is of size 2m x 1.5m and the other 2 windows are of size 1m x 1.5m. The cost of painting the walls at Rs. 3 per sq m is

A) Rs.174	B) Rs.274
C) Rs.374	D) Rs.474

Answer & Explanation Answer: D) Rs.474

Explanation:

Area of 4 walls = 2(l+b)h
=2(10+7) x 5 = 170 sq m
Area of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq m
area to be planted = 170 -12 = 158 sq m

Cost of painting = Rs. 158 x 3 = Rs. 474

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Q:

An error of 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is

A) 4.04%	B) 5.04%
C) 6.04%	D) 7.04%

Answer & Explanation Answer: A) 4.04%

Explanation:

100 cm is read as 102 cm

a = 100 x 100 sq.cm and b = 102 x 102 sq.cm

then, Increase in area = [ (102 x 102) - (100 x 100) ] sq.cm

percentage error = $\frac{404}{100 * 100} * 100$ = 4.04%

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Q:

Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is

A) 1.967	B) 1.867
C) 1.767	D) 1.567

Answer & Explanation Answer: A) 1.967

Explanation:

required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with Ã = 60 degrees and r = 3.5cm)
$(\frac{\sqrt{3}}{4} * 7 * 7) - (3 * \frac{22}{7} * 3.5 * 3.5 * \frac{60}{360})$ sq cm

= $(\frac{\sqrt{3}}{4} * 49) - (11 * 0.5 * 3.5)$ sq cm

= 1.967 sq cm

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Q:

The wheel of a motorcycle 70cm in diameter makes 40 revolutions in every 10sec.What is the speed of motorcycle n km/hr?

A) 13.68kmph	B) 31.68kmph
C) 41.68kmph	D) 45.68kmph

Answer & Explanation Answer: B) 31.68kmph

Explanation:

In this type of question, we will first calculate the distance covered in given time.

Distance covered will be : Number of revolutions x Circumference

So we will be having distance and time, from which we can calculate the speed.

Radius of wheel = 70 / 2 = 35 cm

Distance covered in 40 revolutions will be $40 * c i r c u m f e r e n e = 40 * 2 πr = 40 * 2 * \frac{22}{7} * 35 = 8800 cm$ = 88 m

Distance covered in 1 sec = $\frac{88}{10} = 8.8 m / s = 8.8 * \frac{18}{5} k m / h r = 31.68 k m / h r$

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Q:

A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be

A) 7744	B) 8844
C) 5544	D) 4444

Answer & Explanation Answer: A) 7744

Explanation:

length of wire = $2 πr$ = 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm

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Q:

The ratio of bases of two triangles is x:y and that of their areas is a:b. Then the ratio of their corresponding altitudes wll be

A) ay:bx	B) a:b
C) x:y	D) bx:ay

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