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Q:

Find the number of ways to arrange 4 people in groups of 3 at a time where order matters?

A) 20	B) 16
C) 24	D) 36

Answer & Explanation Answer: C) 24

Explanation:

P(4,3)= ${}^{4}P_{3}$ = 24

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Filed Under: Permutations and Combinations

Q:

If the letters of the word SACHIN are arranged in all possible ways and these words are written out as in dictionary, then the word ‘SACHIN’ appears at serial number :

A) 601	B) 600
C) 603	D) 602

Answer & Explanation Answer: A) 601

Explanation:

If the word started with the letter A then the remaining 5 positions can be filled in 5! Ways.

If it started with c then the remaining 5 positions can be filled in 5! Ways.Similarly if it started with H,I,N the remaining 5 positions can be filled in 5! Ways.

If it started with S then the remaining position can be filled with A,C,H,I,N in alphabetical order as on dictionary.

The required word SACHIN can be obtained after the 5X5!=600 Ways i.e. SACHIN is the 601th letter.

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Filed Under: Permutations and Combinations

Q:

Find the total number of distinct vehicle numbers that can be formed using two letters followed by two numbers. Letters need to be distinct

A) 65000	B) 64000
C) 72000	D) 36000

Answer & Explanation Answer: A) 65000

Explanation:

Out of 26 alphabets two distinct letters can be chosen in $26 P_{2}$ ways. Coming to numbers part, there are 10 ways.(any number from 0 to 9 can be chosen) to choose the first digit and similarly another 10ways to choose the second digit. Hence there are totally 10X10 = 100 ways.

Combined with letters there are $6 P_{2}$ X 100 ways = 65000 ways to choose vehicle numbers.

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Filed Under: Permutations and Combinations

Q:

From 5 consonants and 4 vowels, how many words can be formed using 3 consonants and 2 vowels ?

A) 7600	B) 7200
C) 6400	D) 3600

Answer & Explanation Answer: B) 7200

Explanation:

From 5 consonants, 3 consonants can be selected in $5 C_{3}$ ways.

From 4 vowels, 2 vowels can be selected in $4 C_{2}$ ways.

Now with every selection, number of ways of arranging 5 letters is $5 P_{5}$ ways.

Total number of words = $5 C_{3} * 4 C_{2} * 5 P_{5}$

= 10x 6 x 5 x 4 x 3 x 2 x 1= 7200

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Filed Under: Permutations and Combinations

Q:

What is the SI on Rs.7500/- at the rate of 10% per annum for 5 years?

A) 3750	B) 2750
C) 1750	D) 750

Answer & Explanation Answer: A) 3750

Explanation:

S.I=PNR/100

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What is the SI on Rs.2500/- at the rate of 12% per annum for 8 years?

A) 2200	B) 2300
C) 2400	D) 2500

Answer & Explanation Answer: C) 2400

Explanation:

S.I=PNR/100

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If $n C_{10} = n C_{12}$ then,find n.

A) 10	B) 12
C) 22	D) 24

Answer & Explanation Answer: C) 22

Explanation:

Using, ${}^{n}C_{r} = {}^{n}C_{n - r}$ we get

n – 10 = 12

or, n = 12 + 10 = 22

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Filed Under: Permutations and Combinations

Q:

Payments of $2000 and $1000 were originally scheduled to be paid one year and five years, respectively, from today. They are to be replaced by a $1500 payment due four years from today, and another payment due two years from today. The replacement stream must be economically equivalent to the scheduled stream. What is the unknown payment, if money can earn 7% compounded semiannually?

A) 1548	B) 1348
C) 1648	D) 1748

Answer & Explanation Answer: C) 1648

Explanation:

FV1 = Future value of $2000, 1 year later
= PV (1+ i)^n

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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