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Q:

A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

A) Rs. 258	B) Rs. 358
C) Rs. 458	D) Rs. 558

Answer & Explanation Answer: D) Rs. 558

Explanation:

Area to be plastered = $[2 (l + b) \times h] + (l \times b)$

= $[2 (25 + 12) \times 6] + (25 \times 12) = 744 s q . m$

Cost of plastering = $744 \times \frac{75}{100} = R s . 558$

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Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800	B) 43800
C) 83800	D) 73800

Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Q:

A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

A) rs.58	B) rs.158
C) rs.258	D) rs.358

Answer & Explanation Answer: C) rs.258

Explanation:

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m

cost of graveling = 344 x (75/100) = Rs. 258

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Q:

Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is

A) 22m/s	B) 33m/s
C) 44m/s	D) 55m/s

Answer & Explanation Answer: A) 22m/s

Explanation:

let each wheel make x revolutions per sec. Then $[(2 π * \frac{7}{2} * x) + (2 π * 7 * x)] * 10 = 1980$ $(2 * \frac{22}{7} * \frac{7}{2} * x) + (2 * \frac{22}{7} * \frac{7}{2} * x) = 198$

$66 x = 198$

distance moved by smaller wheel in 3 revolutions

= $2 * \frac{22}{7} * \frac{7}{2} * 3 = 66 c m$

speed of smaller wheel = $\frac{66}{3}$ m/s = 22m/s

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Q:

The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is

A) 240	B) 140
C) 40	D) 340

Answer & Explanation Answer: B) 140

Explanation:

distance covered in 1 revolution = $2 πr$ = 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140

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Q:

The area of a field in the shape of a trapezium measures 1440sq m. The perpendicular distance between its parallel sides is 24cm. If the ratio of the sides is 5:3, the length of the longer parallel side is:

A) 75	B) 85
C) 95	D) 105

Answer & Explanation Answer: A) 75

Explanation:

Area of field = $\frac{1}{2} * (5 x + 3 x) * 24$ = 96x sq.m

96x = 1440 => x = $\frac{1440}{96}$ = 15

Hence, the length of longer parallel side = 5x = 75m

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Q:

If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:

A) 1:1	B) 1:2
C) 1:3	D) 1:4

Answer & Explanation Answer: A) 1:1

Explanation:

A square and a rhombus on the same base are equal in area

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Q:

If a parallelogram with area p, a triangle with area R and a triangle with area T are all constructed on the same base and all have the same altitude, then

A) P=R	B) P=A
C) P=A/2	D) P=2R

Answer & Explanation Answer: A) P=R

Explanation:

let each have base = b and height = h
then p = b*h, R = b*h and T = (1/2) * b*h
so P = R, P = 2T and T = (1/2)*R are all correct statements

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