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Q:

A device on a network is ready to send a frame. What is the first thing that CSMA/CD logic does?

A) Sends a token out to instruct other devices not to send packets. B) Sends a jamming signal out to prevent other hosts from sending packets.
C) Sends a discovery message out to find out if the destination host is on the same subnet. D) Listens to see if the Ethernet is busy.
 
Answer & Explanation Answer: D) Listens to see if the Ethernet is busy.

Explanation:
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Q:

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You are the administrator of network X. You decided to implement RIP in the following topology (click exhibit). You do not want R3 to receive RIP updates. What configuration changes need to be implemented?

A) Implement a passive-interface on R1 B) Nothing needs to be configured
C) Create a sub-interface on R1 D) Change the routing protocol to OSPF
 
Answer & Explanation Answer: A) Implement a passive-interface on R1

Explanation:

Explanation: To block RIP broadcasts on an interface connected to a subnet of a RIP-enabled network add the passive-interface command to the RIP Process

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Q:

Given the following network range 192.168.0.0/24. We want minimum 50 hosts on each of the available subnets. What will be the subnet mask?

A) /24 B) /25
C) /26 D) /27
 
Answer & Explanation Answer: C) /26

Explanation:

Explanation: 50 hosts require 6 bits of the last octet giving us 64 -2 = 62 possible hosts this satisfies our requirement and leaves us 2 bits over for the subnets. The default mask is /24 or 255.255.255.0 adding the 2 bits for the subnets it becomes 255.255.255.192 or /26

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Q:

What type of cable is shown in the exhibit?

imageview

A) AEIA/TIA-232 B) EIA-530
C) X.21 D) V.35
 
Answer & Explanation Answer: D) V.35

Explanation:
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Q:

You are the network administrator and are given the tasks to plan for the future expansion of the network. You decide to subnet the current network of 172.15.0.0. What will be the subnet mask be if every subnet has to allocate 500 hosts.

A) 255.255.0.0 B) 255.0.0.0
C) 255.255.240.0 D) 255.255.254.0
 
Answer & Explanation Answer: D) 255.255.254.0

Explanation:

Explanation: The requirement of having to allocate 500 hosts on each subnet can be achieved by the following: 2^9 = 512. So deducting the broadcast and network address we have 510 possible hosts on each subnet. We used 9 bits to allocate the hosts, this leaves us 7 bits for possible subnets. Those 7 bits in binary is 1111 1110 or 254 in decimal.

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Q:

We want to assign port 3 of our Catalyst 2950 switch to VLAN 3. What command will achieve this?

A) switch(config-if)#switchport vlan 3 B) switch#switchport access vlan 3
C) switch(config)#switchport access vlan 3 D) switch(config-if)#switchport access vlan 3
 
Answer & Explanation Answer: D) switch(config-if)#switchport access vlan 3

Explanation:

Explanation: The switchport access vlan [number] command will configure a switch port to that VLAN. You can also use the switchport access vlan dynamic command to configure the switch port automatically in a certain VLAN depending on the VLAN membership of the incoming packets. For both commands to work properly the switch port needs to be in access mode

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Q:

Assume a router has a loopback address of 135.77.9.254. Convert the loopback address to an IS-IS system ID.

Answer

The loopback address written in dotted decimal and using three digits for each byte has a value of 135.077.009.254. The system ID is 13.50.77.00.92.54.

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Q:

What is the full IPv6 address represented by FF02::130F:5?

Answer

FF02:0000:0000:0000:0000:0000:130F:0005

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Subject: CCNP