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Q:

Find the annual income derived from Rs. 2500, 8% stock at 106?

A) 100	B) 200
C) 150	D) 250

Answer & Explanation Answer: B) 200

Explanation:

Income from Rs. 100 stock = Rs. 8.

Income from Rs. 2500 stock = $R s (\frac{8}{100} * 2500)$ = Rs. 200.

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Filed Under: Stocks and Shares

Q:

What are the disadvantages of context switching?

Answer

Time taken for switching from one process to other is pure over head. Because the system does no useful work while switching. So one of the solutions is to go for threading when ever possible.

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Subject: Operating Systems

Q:

I. A. B, C. D, E and F are six members of a family.

II. One couple has parents and their children in the family.

III. A is the son of C and E is the daughter of A.

IV. D is the daughter of F who is the mother of E.

Which of the following pairs is the parents of the couple ?

A) AB	B) BC
C) AF	D) CF

Answer & Explanation Answer: B) BC

Explanation:

E is the daughter of A and F is the mother of E So, A is the father of E and hence the husband of F. Now,

D is the daughter of F So. D and E are the daughters of A and F Also. A is the son of C.

Now, only B remains Thus. B and C are the parents of A.

Clearly. B and C are the parents of the couple

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Filed Under: Blood Relations

Q:

What is relative path and absolute path?

Answer

Absolute path-- Exact path from root directory.

Relative path-- Relative to the current path.

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Subject: Operating Systems

Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is $7 C_{5}$ .

So,required probability = $7 C_{5}$ / $10 C_{5}$ = 1/12.

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Filed Under: Probability

Q:

A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: A) 5/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is $3 C_{1} * 7 C_{4}$

So,required probability = $3 C_{1} * 7 C_{4}$ / $10 C_{5}$ = 5/12.

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Filed Under: Probability

Q:

What is a device queue?

Answer

A list of processes waiting for a particular I/O device is called device queue.

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Subject: Operating Systems

Q:

A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A) 551/15134	B) 1/2
C) 552/15379	D) 1/9

Answer & Explanation Answer: A) 551/15134

Explanation:

Total number of elementary events = $50 C_{5}$
Given,third ticket =30

=> first and second should come from tickets numbered 1 to 29 = $29 C_{2}$ ways and remaining two in $20 C_{2}$ ways.

Therfore,favourable number of events = $29 C_{2} * 20 C_{2}$

Hence,required probability = $29 C_{2} * 20 C_{2}$ $/ 50 C_{5}$ =551 / 15134

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Filed Under: Probability

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