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Q:

A man invests Rs.5000 for 3 years at 5% p.a. compound interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the third year

A) Rs.5624.32	B) Rs.5423
C) Rs.5634	D) Rs.5976

Answer & Explanation Answer: A) Rs.5624.32

Explanation:

5% is the rate of interest. 20% of the interest amount is paid as tax.

i.e 80% of the interest amount stays back.

$\therefore$ if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value.

The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest.

= 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32

The amount at the end of 3 years = 5000 + 624.32 = 5624.32

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Q:

The population of a town was 3600 three years back. It is 4800 right now. What will be the population three years down the line, if the rate of growth of population has been constant over the years and has been compounding annually?

A) Rs.600	B) Rs,6400
C) Rs.6500	D) Rs.6600

Answer & Explanation Answer: B) Rs,6400

Explanation:

The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.

Therefore, the rate of growth for three years has been constant.

The rate of growth during the next three years will also be the same.

Therefore, the population will grow from 4800 by $4800 * \frac{1}{3}$ = 1600

Hence, the population three years from now will be 4800 + 1600 = 6400

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Q:

What will Rs.1500 amount to in three years if it is invested in 20% p.a. compound interest, interest being compounded annually?

A) Rs.2592	B) Rs.2492
C) Rs.2352	D) Rs.2352

Answer & Explanation Answer: A) Rs.2592

Explanation:

The usual way to find the compound interest is given by the formula A = .p(1+r/100)^n

In this formula,

A is the amount at the end of the period of investment

P is the principal that is invested

r is the rate of interest in % p.a

And n is the number of years for which the principal has been invested.

In this case, it would turn out to be A =1500(1+20/100)^3

= 2592.

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Q:

The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is

A) 6.06%	B) 6.07%
C) 6.08%	D) 6.09%

Answer & Explanation Answer: D) 6.09%

Explanation:

Amount of Rs. 100 for 1 year

when compounded half-yearly = Rs.[100*(1+3/100)^2]=Rs.106.09

Effective rate=(106.09-100)%=6.09%

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Q:

Albert invested an amount of Rs. 8000 in a fixed deposit scheme for 2 years at compound interest rate 5 p.c.p.a. How much amount will Albert get on maturity of the fixed deposit

A) Rs.8820	B) Rs.8620
C) Rs.8520	D) Rs.8320

Answer & Explanation Answer: A) Rs.8820

Explanation:

Amount = $R s . [8000 * {(1 + \frac{5}{100})}^{2}]$ =Rs.8820

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Q:

The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:

A) 3	B) 4
C) 5	D) 6

Answer & Explanation Answer: B) 4

Explanation:

$P {(1 + \frac{20}{100})}^{n} > 2 P \Leftrightarrow {(\frac{6}{5})}^{n} > 2$

$(\frac{6}{5} \times \frac{6}{5} \times \frac{6}{5} \times \frac{6}{5}) > 2$

so, answer is 4 years

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Q:

What is the rate of compound interest?
I. The principal was invested for 4 years.
II. The earned interest was Rs. 1491.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Either I or II alone sufficient to answer

Answer & Explanation Answer: D) Either I or II alone sufficient to answer

Explanation:

Let Principal = Rs. P and Rate = R% p.a. Then,

Amount= $R s . [P {(1 + \frac{R}{100})}^{4}]$

C.I = $P [{(1 + \frac{R}{100})}^{4} - 1]$

$P [{(1 + \frac{R}{100})}^{4} - 1] = 1491$

Clearly, it does not give the answer

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Q:

The difference between the simple interest on a certain sum at the rate of 10%per annum for 2 years and compound interest which is compounded every 6 months is Rs.124.05. what is the principal sum

A) Rs.6000	B) Rs.8000
C) Rs.12000	D) none of these

Answer & Explanation Answer: B) Rs.8000

Explanation:

Compound Interest on P at 10% for 2 years when interest is compounded half-yearly

= $P {(1 + \frac{\frac{R}{2}}{100})}^{2 T} - P = P {(1 + \frac{1}{20})}^{4} - P = P {(\frac{21}{20})}^{4} - P$

Simple Interest on P at 10% for 2 years = $\frac{P R T}{100} = \frac{P \times 10 \times 2}{100} = \frac{P}{5}$

Given that difference between compound interest and simple interest = 124.05

$P * {(\frac{21}{20})}^{4} - P - \frac{P}{5} = 124.05$

=> $P [{(\frac{21}{20})}^{4} - 1 - \frac{1}{5}] = 124.05$

P=8000

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