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Q:

If the binary equivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what would be the output of the following program?

main()

{

    float a = 5.375 ;

    char *p;

    int i;

    p = ( char* ) &a ;

    for ( i = 0; i <= 3 ; i++ )

          printf ( " %02x ", (unsigned char ) p[i] );

}

Answer

00 00 AC 40

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

    printf (" %d%d%d ", sizeof (3.14f), sizeof (3.14), sizeof (3. 141);

}

Answer

4  8  10

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Subject: Programming

Q:

Which error are you likely to get when you run the following program?

main()

{

  struct emp

  {

      char name[20];

      float sal;

  };

  struct emp e[10];

  int i;

  for ( i = 0 ; i <= 9; i++)

        scanf ( "%s %f" , e[i].name, &e[i].sal );

}

Answer

Floating point formats not linked

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Subject: Programming

Q:

We want to round off x, a Float to an Int value. The correct way to do so would be

A) Y = ( int ) ( x + 0.5 ) ; B) Y = int ( x + 0.5) ;
C) Y = ( int ) x + 0.5; D) Y = ( int ) ( ( int ) x + 0.5 )
 
Answer & Explanation Answer: A) Y = ( int ) ( x + 0.5 ) ;

Explanation:

Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.

 

y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)

 

Example:

 

#include

 

int main ()

 

{

 

  float x = 2.6;

 

  int y = (int)(x + 0.5);

 

  printf ("Result = %d\n", y );

 

  return 0;

 

}

 

Result : 3

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Filed Under: Programming

Q:

What would be the output of the following program?

main()

{

    int i = -3, j =2, k =0, m ;

    m = ++j && ++i || ++k ;

    Printf ( "\n%d%d%d%d", i , j , k , m );

}

Answer

-2  3  0  1

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Subject: Programming

Q:

Can you suggest any other way of writing the following expression such that 30 is used only once?

a <= 20 ? b = 30 : c = 30 ;

Answer

*( ( a <= 20 ) ? &b : &c ) = 30;

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

  int i=2 ;

  printf ("\n%d%d", ++i, ++i );

}

Answer

Output may vary from compiler to compiler.


The order of evaluation of the arguments to a function call is unspecified.

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

    static int a[20];

    int i = 0;

    a[i] = i++;

    printf ("\n%d%d%d", a[0],  a[1], i);

}

Answer

0  0  1


That's what some of the compilers would give. But some other compiler may give a different answer. The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined.

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Subject: Programming