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Q:

The current birth rate per thousand is 32, whereas corresponding death rate is 11 per thousand. The net growth rate in terms of population increase in percent is given by :

A) 1.2 %	B) 2.1 %
C) 3.1 %	D) 1.3 %

Answer & Explanation Answer: B) 2.1 %

Explanation:

Net growth on 1000 = (32 - 11) = 21. Net growth on 100 =(21/1000 * 100) %= 2.1%.

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Q:

If the pice of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in his expenditure on sugar, will have to reduce his consumpion of sugar by

A) 15	B) 20
C) 25	D) 30

Answer & Explanation Answer: B) 20

Explanation:

Let original consumption = 100 kg and new consumption = x kg,

So, 100 * 6 = x * 7.50 => x = 80kg

Reduction in consumption = 20%.

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Q:

In a hoel, 60% had vegetarian lunch while 30% had non-vegetaian lunch and 15% had both types of lunch. If 96 people were present, how many did not eat either type of lunch ?

A) 24	B) 30
C) 36	D) 42

Answer & Explanation Answer: A) 24

Explanation:

n (A) = (60/100 * 96) = 288/5, n (B) = (30/100 * 96) = 144/5, n (A ∩ B) = (15/100 * 96) = 72/5.

n(A ∪ B) = n (A) + n (B) - n (A ∩ B) = 72.

So, people who had either or both types of lunch = 72.

Hence, people who had neither type of lunch = (96 - 72)= 24.

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Q:

405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: A) 9

Explanation:

Let the total number of children be x.

Then, x * (20% of x) = 405

=> x * 20x/100 = 405

$\frac{1}{5} x^{2}$ = 405

=> x=45

Number of sweets received by each child = 20% of 45 = 9.

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Q:

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was :

A) 10000	B) 12000
C) 14000	D) 16000

Answer & Explanation Answer: B) 12000

Explanation:

Purchase price = $R s . [\frac{8748}{{^{(1 - \frac{10}{100})}}^{3}}]$ = Rs. [8748 * (10/9) * (10/9 )* (10/9)] = Rs.12000

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Q:

In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is female while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728400, what is its female population ?

A) 324138	B) 349680
C) 509940	D) None of these

Answer & Explanation Answer: A) 324138

Explanation:

Total Population = 728400

Migrants = 35 % of 728400 = 254940

$\therefore$ local population = (728400 - 254940) = 473460.

Rural migrants = 20% of 254940 = 50988

Urban migrants = (254940 - 50988) = 203952

Female population = 48% of 473460 + 30% of 50988 + 40% of 203952 = 324138

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Q:

In a History examination, the average for the entire class was 80 marks. If 10% of the students scored 35 marks and 20% scored 90 marks, what was the average marks of the remaining students of the class ?

A) 25	B) 50
C) 75	D) 100

Answer & Explanation Answer: C) 75

Explanation:

Let the number of students in the class be 100 and let this required average be x.

Then, (10 * 95) + (20 * 90) + (70 * x) = (100 * 80)

=> 70x = 8000 - (950 + 1800) = 5250

=> x = 75.

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Q:

While purchasing one item costing Rs. 400, I had to pay the sales tax at 7% and on another costing Rs. 6400, the sales tax was 9%. What percent of the sales tax I had to pay, taking the two items together on an average ?

A) 8 + 15/17	B) 2 + 13/17
C) 3 + 2/17	D) 5 + 13/12

Answer & Explanation Answer: A) 8 + 15/17

Explanation:

Total sales tax paid = 7% of Rs, 400 + 9% of Rs. 6400

=Rs. (7/100)*400 + (9/100)*6400 = Rs. (28 + 576) = Rs. 604.

Total cost of the items = Rs. (400 + 6400) = Rs. 6800.

Required percentage =(604/6800*100) % = $8 \frac{15}{17}$ %.

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