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Q:

What is busy waiting?

Answer

The repeated execution of a loop of code while waiting for an event to occur is called busy-waiting. The CPU is not engaged in any real productive activity during this period, and the process does not progress toward completion.

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Q:

What is virtual channel?

Answer

Virtual channel is normally a connection from one source to one destination, although multicast connections are also permitted. The other name for virtual channel is virtual circuit.

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Subject: Networking
Job Role: Network Engineer

Q:

What are the stipulations of C2 level security?

Answer

C2 level security provides for:


 


1.Discretionary Access Control


2.Identification and Authentication


3.Auditing


4.Resource reuse

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Q:

What is cycle stealing?

Answer

We encounter cycle stealing in the context of Direct Memory Access (DMA). Either the DMA controller can use the data bus when the CPU does not need it, or it may force the CPU to temporarily suspend operation. The latter technique is called cycle stealing. Note that cycle stealing can be done only at specific break points in an instruction cycle.

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Q:

What is the resident set and working set of a process?

Answer

Resident set is that portion of the process image that is actually in real-memory at a particular instant. Working set is that subset of resident set that is actually needed for execution. (Relate this to the variable-window size method for swapping techniques.)

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Q:

What is virtual path?

Answer

Along any transmission path from a given source to a given destination, a group of virtual circuits can be grouped together into what is called path.

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Subject: Networking
Job Role: Network Engineer

Q:

If p:q are the odds in favour of an event,then the probability of that event is:

A) p/q B) p/(p+q)
C) q/(p+q) D) none
 
Answer & Explanation Answer: B) p/(p+q)

Explanation:

Total number of cases=p+q

Favourable cases=p

Probability of that event is=p/(p+q)

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Filed Under: Probability

Q:

The probabiltiy that throw of two dice yields a total of 5 or 6 is:

A) 2/14 B) 5/18
C) 3/4 D) 1/4
 
Answer & Explanation Answer: B) 5/18

Explanation:

Total number of cases=36

Number of favourable cases(sum 5 or 6)=10

P(getting total of 5 or 6)=10/36=5/18

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Filed Under: Probability