Searching for "style"

Q:

tan3A is equal to

A) 3tanA -­ tan3A(1 -­ 3tan2A) B) 3tanA + tan3A(1 -­ 3tan2A)
C) 3tanA -­ tan3A(1 + 3tan2A) D) 3tanA + tan3A(1 + 3tan2A)
 
Answer & Explanation Answer: A) 3tanA -­ tan3A(1 -­ 3tan2A)

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

Q:

If 3x2 = 102 - 52, find the value of x?

A) 7 B) 5
C) 9 D) 11
 
Answer & Explanation Answer: B) 5

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

Q:

If  tan2A / (secA -­ 1)2 = x, then the value of x is

A) (1+cosecA) / (1­-cosecA) B) (1+cosA)(1-­cosA)
C) (1+cosA) / (1­-cosA) D) (1+cosecA)(1­-cosecA)
 
Answer & Explanation Answer: C) (1+cosA) / (1­-cosA)

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

Q:

tanAcosec2A is equal to

A) (1 + tan2A)cotA B) (1 -­ tan2A)cotA
C) √[(1 + tan2A)cotA] D) √[(1 -­ tan2A)cotA]
 
Answer & Explanation Answer: A) (1 + tan2A)cotA

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

Q:

2 ­- (cosA + sinA)2 is equal to

A) (cosecA -­ sinA)2 B) cosA ­- sinA
C) cosecA ­- sinA D) (cosA -­ sinA)2
 
Answer & Explanation Answer: D) (cosA -­ sinA)2

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

Q:

On dividing 221a2b2 by 13b2, we get _____.

A) 17a2 B) 17b2
C) 13a2b2 D) 13
 
Answer & Explanation Answer: A) 17a2

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

Q:

Coefficient of x2 in 4x3 - 2x2 + 2x -­ 3 are

A) 6 B) -2
C) 3 D) -3
 
Answer & Explanation Answer: B) -2

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams , CAT

Q:

What is the value of 2sec2A?

A) secA/(cosecA - ­1) + secA/(cosecA +1) B) cosecA/(secA -­1) + cosecA/(secA +1)
C) cosecA/(cosecA - ­1) + cosecA/(cosecA +1) D) secA/(secA - ­1) + secA/(secA +1)
 
Answer & Explanation Answer: C) cosecA/(cosecA - ­1) + cosecA/(cosecA +1)

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams