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Q:

The perimeter of a rectangle is 160 cm. The rectangle is 4 times longer than wide. What are the length and width of this rectangle?

A) l=65;b=16	B) l=16;b=64
C) l=64;b=16	D) l=16;b=48

Answer & Explanation Answer: C) l=64;b=16

Explanation:

P=2(l+b)

l=4b

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Q:

The length of a rectangular plot is 20 meters more than its breadth. If the cost of fencing the plot @ 26.50 per meter is Rs. 5300. What is the length of the plot in meter?

A) 40m	B) 50m
C) 60m	D) 10m

Answer & Explanation Answer: C) 60m

Explanation:

let breadth = x then length = x+20

perimeter = 5300/26.50 = 200m

2(x+20+x) =200 => 4x+40 =200

x = 40 and length = 40+20 = 60m

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Q:

A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?

A) 65m	B) 45m
C) 55m	D) 56m

Answer & Explanation Answer: D) 56m

Explanation:

perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m

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Q:

The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter

A) Rs.16500	B) Rs.15500
C) Rs.17500	D) Rs.18500

Answer & Explanation Answer: A) Rs.16500

Explanation:

l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500

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Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m	B) 16m
C) 14m	D) 76m

Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts

then, ${πr}^{2} = 9856 \Rightarrow r^{2} = \frac{9856 \times 7}{22} = 3136 \Rightarrow r = 56 m$

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Q:

The base of a triangle of 15cm and height is 12cm. The height of another triangle of double the area having the base 20cm is

A) 16	B) 17
C) 18	D) 20

Answer & Explanation Answer: C) 18

Explanation:

a = $\frac{1}{2} \times 15 \times 12$ = 90 sq.cm

b = 2a = $\frac{1}{2} \times 20 \times h$

h= 18cm

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Q:

A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

A) Rs. 258	B) Rs. 358
C) Rs. 458	D) Rs. 558

Answer & Explanation Answer: D) Rs. 558

Explanation:

Area to be plastered = $[2 (l + b) \times h] + (l \times b)$

= $[2 (25 + 12) \times 6] + (25 \times 12) = 744 s q . m$

Cost of plastering = $744 \times \frac{75}{100} = R s . 558$

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Q:

If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

A) a	B) a>b
C) a=b	D) none

Answer & Explanation Answer: B) a>b

Explanation:

Take a square of side 4cm and a rectangle having l=6cm and b=2cm

then perimeter of square = perimeter of rectangle

area of square = 16 sq.cm

area of rectangle = 12 sq.cm

Hence a >b

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