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Q:

There is a mistake in the following code. Add a statement in it to remove it.

main()

{

     int a;

     a = f (10, 3.14) ;

     printf ( " %d ", a );

}

f (int aa, float bb)

{

    return ( ( float ) aa + bb );

}

Answer

Add the following function prototype in main ():


float f ( int, float );

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

    float a = 0.7;

    if ( a < 0.7f )

          printf ( " C ");

    else 

          Printf ( " C++ ");

}

Answer

C++

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Subject: Programming

Q:

If the binary equivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what would be the output of the following program?

main()

{

    float a = 5.375 ;

    char *p;

    int i;

    p = ( char* ) &a ;

    for ( i = 0; i <= 3 ; i++ )

          printf ( " %02x ", (unsigned char ) p[i] );

}

Answer

00 00 AC 40

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

    printf (" %d%d%d ", sizeof (3.14f), sizeof (3.14), sizeof (3. 141);

}

Answer

4  8  10

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Subject: Programming

Q:

Which error are you likely to get when you run the following program?

main()

{

  struct emp

  {

      char name[20];

      float sal;

  };

  struct emp e[10];

  int i;

  for ( i = 0 ; i <= 9; i++)

        scanf ( "%s %f" , e[i].name, &e[i].sal );

}

Answer

Floating point formats not linked

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Subject: Programming

Q:

We want to round off x, a Float to an Int value. The correct way to do so would be

A) Y = ( int ) ( x + 0.5 ) ; B) Y = int ( x + 0.5) ;
C) Y = ( int ) x + 0.5; D) Y = ( int ) ( ( int ) x + 0.5 )
 
Answer & Explanation Answer: A) Y = ( int ) ( x + 0.5 ) ;

Explanation:

Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.

 

y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)

 

Example:

 

#include

 

int main ()

 

{

 

  float x = 2.6;

 

  int y = (int)(x + 0.5);

 

  printf ("Result = %d\n", y );

 

  return 0;

 

}

 

Result : 3

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Filed Under: Programming

Q:

What would be the output of the following program?

main()

{

    int i = -3, j =2, k =0, m ;

    m = ++j && ++i || ++k ;

    Printf ( "\n%d%d%d%d", i , j , k , m );

}

Answer

-2  3  0  1

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Subject: Programming

Q:

In the following code in which order the functions would be called?

a = ( f1 ( 23,14 ) * f2 ( 12/4) ) + f3() ;

Answer

The order may vary from compiler to compiler.


Here the multiplication will happen before the addition , but in which order the functions would be called is undefined. In an arithmetic expression the parentheses tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parentheses first.

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Subject: Programming