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Q:

At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?

A) Rs.2500 B) Rs.2000
C) Rs.4000 D) None of these
 
Answer & Explanation Answer: C) Rs.4000

Explanation:

Maximum earning will be only when he will won on the maximum yielding table.

     A ----> 10:1

     B ----> 20:1

     C ----> 30:1

 i.e, he won on B and C but lost on A

 20 x 200 + 30 x 200 -1 x 200 = 9800

 minimum earning will be when he won on  table A and B and lose on that table 3.

 

Therefore, 10 x 200 + 20 x 200 - 1 x 200  =  6000-200 = 5800

Therefore, Difference= 9800 - 5800 = 4000

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Filed Under: Ratios and Proportions

Q:

The ratio of students in a coaching preparing for B.tech and MBA is 4 : 5. The ratio of fees collected from each of B.tech and MBA students is 25 : 16. If the total amount collected from all the students is 1.62 lakh, what is the total amount collected from omly MBA aspirants?

A) Rs. 62,000 B) Rs. 72,000
C) Rs. 82,000 D) None of these
 
Answer & Explanation Answer: B) Rs. 72,000

Explanation:

The ratio of fees collected from B.Tech : MBA = 4x * 25y : 5x * 16y 

                                                                  = 100xy : 80xy 

                                                                  = 5xy : 4 xy  = 5k : 4k

 

The amount collected only from MBA students = 49×1.62 lakh = Rs. 72,000

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Filed Under: Ratios and Proportions

Q:

A, B and C have amounts in the ratio of  3 : 4 : 5. First B gives 1/4th to A and 1/4th to C then C gives 1/6th to A. Find the final ratio of amount of A, B and C respectively.

A) 4:3:5 B) 5:4:3
C) 3:4:5 D) 5:2:5
 
Answer & Explanation Answer: D) 5:2:5

Explanation:

A                   B                 C

 

3x                 4x                5x 

(3x+x)          2x               (5x+x)         (B Gives 1/4 to A and 1/4 to C) 

=4x              2x                 6x 

(4x+x)          2x                 5x              ( C Gives 1/6 to A) 

=5x              2x                 5x

 

Therefore, 5 : 2 : 5

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Filed Under: Ratios and Proportions

Q:

6 pumps of kirlosker can fill a tank in 7 days and 2 similar pumps of USHA can fill the same tank in 18 days. what is the ratio of the efficiency of a kirlosker pump and a USHA pump?

A) 6:7 B) 7:6
C) 7:54 D) None of these
 
Answer & Explanation Answer: A) 6:7

Explanation:

The number of days required by a single kirlosker pump to fill the tank = 6 x 7 =42 days and the number of days required by a single USHA pump to fill the same tank = 2 x 18 =36 days.

Now , since efficiency is inversely proportional to the number of days. Hence,

Efficiency of one K - pumpEfficiency of U- pump=3642=67  

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Filed Under: Ratios and Proportions

Q:

For any two numbers m , n ; (m+n) : (m-n) : mn = 7: 1: 60 . Find the value of 1/m : 1/n

A) 4:3 B) 8:7
C) 3:4 D) 7:8
 
Answer & Explanation Answer: C) 3:4

Explanation:

m+nm-n=7xx mn=4x3x  

 

Again   mn=12x2 

 

and         mn =60x  

 

so, 60x=12x2 x=5    

 

=>  m= 20  and    n= 15

 

Hence,    1m:1n=120:115=3:4

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Filed Under: Ratios and Proportions

Q:

The concentration of petrol in three different mixtures (petrol and kerosene) is 1/2 , 3/5 and 4/5 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. what is the ratio of petrol and kerosene in the new mixture?

A) 4:5 B) 3:2
C) 3:5 D) 2:3
 
Answer & Explanation Answer: B) 3:2

Explanation:

Concentration of petrol in    A        B        C

                                                1/2      3/5     4/5

Quantity of petrol taken from A = 1 litre out of 2 litre

Quantity of petrol taken from B = 1.8litre out of 3 litre

Quantity of petrol taken from C = 0.8 litre out of 1 litre

Therefore, total petrol taken out from A, B and C = 1+1.8+0.8 =3.6 litres

So, the quantity of kerosen =(2+3+1) - 3.6 =2.4 litre

Thus, the ratio of petrol to kerosene = 3.6/2.4 = 3/2

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Filed Under: Ratios and Proportions

Q:

A child has three different kinds of chocolates costing  Rs.2, Rs.5, Rs.10.  He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be  atleast one chocolate of each kind?

A) 22 B) 19
C) 17 D) 15
 
Answer & Explanation Answer: C) 17

Explanation:

Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.

Thus,          2 x 5 + 5 x 2 =Rs.20

Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.

Thus minumum number of chocolates = 5 + 2 + 10 = 17

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Filed Under: Ratios and Proportions

Q:

“One People, One State, One leader” was the policy of

A) Stalin B) Hitler
C) Lenin D) Mussolin
 
Answer & Explanation Answer: B) Hitler

Explanation:
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Filed Under: General Awareness