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Q:

Find the total number of distinct vehicle numbers that can be formed using two letters followed by two numbers. Letters need to be distinct

A) 65000	B) 64000
C) 72000	D) 36000

Answer & Explanation Answer: A) 65000

Explanation:

Out of 26 alphabets two distinct letters can be chosen in $26 P_{2}$ ways. Coming to numbers part, there are 10 ways.(any number from 0 to 9 can be chosen) to choose the first digit and similarly another 10ways to choose the second digit. Hence there are totally 10X10 = 100 ways.

Combined with letters there are $6 P_{2}$ X 100 ways = 65000 ways to choose vehicle numbers.

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Filed Under: Permutations and Combinations

Q:

How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?

A) 1000	B) 100
C) 500	D) 999

Answer & Explanation Answer: B) 100

Explanation:

1 million distinct 3 digit initials are needed.

Let the number of required alphabets in the language be ‘n’.

Therefore, using ‘n’ alphabets we can form n * n * n = $n^{3}$ distinct 3 digit initials.

Note distinct initials is different from initials where the digits are different.

For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different.

This $n^{3}$ different initials = 1 million

i.e. $n^{3} = 10^{6}$ (1 million = $10^{6}$ )

=> n = $10^{2}$ = 100

Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.

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Filed Under: Permutations and Combinations

Q:

In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?

A) 135	B) 63
C) 125	D) 64

Answer & Explanation Answer: B) 63

Explanation:

Required number of ways = $(7 C_{5} * 3 C_{2}) = (7 C_{2} * 3 C_{1}) = 63$

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Filed Under: Permutations and Combinations

Q:

When four fair dice are rolled simultaneously, in how many outcomes will at least one of the dice show 3?

A) 620	B) 671
C) 625	D) 567

Answer & Explanation Answer: B) 671

Explanation:

When 4 dice are rolled simultaneously, there will be a total of 6 x 6 x 6 x 6 = 1296 outcomes.

The number of outcomes in which none of the 4 dice show 3 will be 5 x 5 x 5 x 5 = 625 outcomes.

Therefore, the number of outcomes in which at least one die will show 3 = 1296 – 625 = 671

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Filed Under: Permutations and Combinations

Q:

From 5 consonants and 4 vowels, how many words can be formed using 3 consonants and 2 vowels ?

A) 7600	B) 7200
C) 6400	D) 3600

Answer & Explanation Answer: B) 7200

Explanation:

From 5 consonants, 3 consonants can be selected in $5 C_{3}$ ways.

From 4 vowels, 2 vowels can be selected in $4 C_{2}$ ways.

Now with every selection, number of ways of arranging 5 letters is $5 P_{5}$ ways.

Total number of words = $5 C_{3} * 4 C_{2} * 5 P_{5}$

= 10x 6 x 5 x 4 x 3 x 2 x 1= 7200

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Filed Under: Permutations and Combinations

Q:

What is the SI on Rs.7500/- at the rate of 10% per annum for 5 years?

A) 3750	B) 2750
C) 1750	D) 750

Answer & Explanation Answer: A) 3750

Explanation:

S.I=PNR/100

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What is the SI on Rs.2500/- at the rate of 12% per annum for 8 years?

A) 2200	B) 2300
C) 2400	D) 2500

Answer & Explanation Answer: C) 2400

Explanation:

S.I=PNR/100

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If $n C_{10} = n C_{12}$ then,find n.

A) 10	B) 12
C) 22	D) 24

Answer & Explanation Answer: C) 22

Explanation:

Using, ${}^{n}C_{r} = {}^{n}C_{n - r}$ we get

n – 10 = 12

or, n = 12 + 10 = 22

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Filed Under: Permutations and Combinations

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