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Q:

How many iron rods, each of length 7 mts and diameter 2 cms can be made out of 0.88 cubic metre of iron ?

A) 500	B) 600
C) 400	D) 300

Answer & Explanation Answer: C) 400

Explanation:

Given length of iron rod =7 mts and and diameter of rod = 2 cms

=> r = 1/100 mts

Therefore, Volume of one rod = ${πr}^{2} h$ cu. m = $(\frac{22}{7} \times {[\frac{1}{100}]}^{2} \times 7)$ cu. m = $\frac{11}{5000}$ cu. m

Given volume of iron = 0.88 cu. m

Therefore, Number of rods = $(0.88 \times \frac{5000}{11})$ = 400.

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Filed Under: Volume and Surface Area
Exam Prep: CAT
Job Role: Bank PO

Q:

Find the ratio of the areas of the incircle and circumcircle of a square ?

A) 1 : 4	B) 4 : 1
C) 2 : 1	D) 1 : 2

Answer & Explanation Answer: D) 1 : 2

Explanation:

Let the side of the square be x. Then, its diagonal = $\sqrt{2} x$ .

Radius of incircle = x/2 and radius of circumcircle = $\frac{\sqrt{2} x}{2}$ . k11482389216.png image

Therefore, required ratio = $(\frac{{πx}^{2}}{4} : \frac{{πx}^{2}}{2})$ = $\frac{1}{4} : \frac{1}{2} = 1 : 2$

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Filed Under: Area
Exam Prep: CAT
Job Role: Bank Clerk

Q:

A container contains 50 litres of milk. From that 8 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container ?

A) 24.52 litres	B) 29.63 litres
C) 28.21 litres	D) 25.14 litres

Answer & Explanation Answer: B) 29.63 litres

Explanation:

Given that container has 50 litres of milk.

After replacing 8 litres of milk with water for three times, milk contained in the container is:

$\Rightarrow [50 {(1 - \frac{8}{50})}^{3}]$

$\Rightarrow (50 \times \frac{42}{50} \times \frac{42}{50} \times \frac{42}{50})$ = 29.63 litres.

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Filed Under: Alligation or Mixture
Exam Prep: CAT
Job Role: Bank PO

Q:

If $3^{x - y} = 27$ , $3^{x + y} = 243$ then find the x value

A) 2	B) 8
C) 4	D) 1

Answer & Explanation Answer: C) 4

Explanation:

Given that $3^{x - y} = 27$ , $3^{x + y} = 243$

$\Rightarrow 3^{x - y} = 3^{3}, 3^{x + y} = 3^{5}$

=> x-y=3, x+y=5

=> x = 4

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Filed Under: Simplification
Exam Prep: CAT
Job Role: Bank Clerk

Q:

A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs.100 at the end of one year. In order clear his dues at the end of 2 years, he would pay :

A) Rs. 100	B) Rs. 105
C) Rs. 115	D) Rs. 110

Answer & Explanation Answer: C) Rs. 115

Explanation:

Amount to be paid = $R s . [100 + \frac{200 \times 5 \times 1}{100} + \frac{100 \times 5 \times 1}{100}]$ = Rs. 115.

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Filed Under: Simple Interest
Exam Prep: CAT
Job Role: Bank Clerk

Q:

3125 256 ? 4 1

Which number replaces the "?" in the question?

A) 27	B) 128
C) 32	D) 64

Answer & Explanation Answer: A) 27

Explanation:

In the given series numbers are arranged following the rule,

$5^{5}, 4^{4}, 3^{3}, 2^{2}, 1^{1}$

Therefore, the missing number is 27.

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Filed Under: Odd Man Out
Exam Prep: CAT
Job Role: Bank PO

Q:

${(31)}^{31} \times {(31)}^{- 27} = ?$

A) 961 x 861	B) 961 x 961
C) 961 x 2	D) 29791

Answer & Explanation Answer: B) 961 x 961

Explanation:

We know that $a^{m} \times a^{n} = a^{m + n}$

$∴ {(31)}^{31 - 27}$ = $31^{4}$ = 961 x 961.

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Filed Under: Numbers
Exam Prep: CAT
Job Role: Bank PO

Q:

A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is :

A) 9.5 km/hr	B) 10 km/hr
C) 10.5 km/hr	D) 11 km/hr

Answer & Explanation Answer: B) 10 km/hr

Explanation:

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.

Therefore, Man's rate against the current = (12.5 - 2.5) = 10 km/hr.

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Filed Under: Problems on Trains
Exam Prep: CAT
Job Role: Bank PO

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