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Q:

In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7.

A) 1/2	B) 5/12
C) 7/15	D) 3/12

Answer & Explanation Answer: B) 5/12

Explanation:

Here n(S) = (6 x 6) = 36

Let E = event of getting a total more than 7
= {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}

Therefore,P(E) = n(E)/n(S) = 15/36 = 5/12.

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Filed Under: Probability

Q:

Find the cost of Rs. 6400, 10% stock at 15 discount?

A) 2000	B) 5440
C) 6000	D) 5140

Answer & Explanation Answer: B) 5440

Explanation:

Cost of Rs. 100 stock = Rs. (100-15)

Cost of Rs. 6400 stock = $R s . \frac{85}{100} * 6400$ = Rs. 5440.

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Filed Under: Stocks and Shares

Q:

Find the cost of Rs. 4500, 8.5% stock at 4 premium?

A) 1400	B) 5000
C) 4000	D) 4680

Answer & Explanation Answer: D) 4680

Explanation:

Cost of Rs. 100 stock = Rs. (100+4) = Rs.104

Cost of Rs. 4500 stock = $R s . \frac{104}{100} \times 4500$ = Rs. 4680

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Filed Under: Stocks and Shares

Q:

An unbiased die is tossed.Find the probability of getting a multiple of 3.

A) 1/3	B) 1/2
C) 3/4	D) 3/2

Answer & Explanation Answer: A) 1/3

Explanation:

Here S = {1,2,3,4,5,6}

Let E be the event of getting the multiple of 3

Then, E = {3,6}

P(E) = n(E)/n(S) = 2/6 = 1/3

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Q:

A family consists of six members P, Q, R, X, Y and Z. Q is the son of R but R is not mother of Q. P and R are a married couple. Y is the brother of R. X is the daughter of P. Z is the brother of P. Which is a pair of brothers ?

A) P and X	B) P and Z
C) Q and X	D) R and Y

Answer & Explanation Answer: D) R and Y

Explanation:

Q is the son of R but R is not the mother. So, R is the Father of Q. P is married to R

So, P is the wife of R and the mother of Q, X is the daughter of P and hence of R and so she is the Sister of Q, Y is the brother of R and Z is the brother of P.

Clearly. Y is brother of R who is a male. So, Y and R are a pair of brothers

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Filed Under: Blood Relations

Q:

Two unbiased coin are tossed. What is the probability of getting atmost one head?

A) 1/2	B) 3/2
C) 1/6	D) 3/4

Answer & Explanation Answer: D) 3/4

Explanation:

Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4

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Q:

Find the probability that one ball is white when two balls are drawn at random from a basket that contains 9 red, 7 white and 4 black balls.

A) 18/95	B) 18/190
C) 1/2	D) 91/190

Answer & Explanation Answer: D) 91/190

Explanation:

Total number of elementary events = $20 C_{2}$ ways =190

There are 7 white balls out of which one white can be drawn in 7 $C_{1}$ ways and one ball from remaining 13 balls can be drawn in $13 C_{1}$ ways.

So,favourable events = $7 C_{1} * 13 C_{1}$

Therfore,required probability = ( $7 C_{1} * 13 C_{1}$ )/ $20 C_{2}$ =91/90

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Q:

One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.

A) 1/3	B) 1/2
C) 1/4	D) 1/6

Answer & Explanation Answer: B) 1/2

Explanation:

Total number of elementary events = 52

There are 26 red cards,out of which one red card can be drawn in $26 C_{1}$ ways =26.

So,required probability = 26/52 = 1/2

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Filed Under: Probability

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