M Search

Q:

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A) 1520 sq.m	B) 2420 sq.m
C) 2480 sq.m	D) 2520 sq.m

Answer & Explanation Answer: D) 2520 sq.m

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) sq.m

= 2520 sq.m

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Q:

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

A) 814	B) 820
C) 840	D) 844

Answer & Explanation Answer: A) 814

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) sq.cm

Required number of tiles = 1517 x (902/41) x 41 = 814

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Q:

The diagonal of a rectangle is sqrt(41) cm. and its area is 20 sq. cm. The perimeter of the rectangle must be:

A) 9 cm	B) 18 cm
C) 20 cm	D) 41 cm

Answer & Explanation Answer: B) 18 cm

Explanation:

$l^{2} + b^{2}$ = ${(d i a g o n a l)}^{2}$ =40

Also, lb=20

${(l + b)}^{2} = l^{2} + b^{2} + 2 l b$ = 41 + 40 =81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Q:

The diagonal of the floor of a rectangular closet is $7 \frac{1}{2}$ feet. The shorter side of the closet is $4 \frac{1}{2}$ feet. What is the area of the closet in square feet?

A) 5 .5	B) 13.5
C) 27	D) 37

Answer & Explanation Answer: C) 27

Explanation:

Other side= $\sqrt{[{(\frac{15}{2})}^{2} - (\frac{9^{2}}{2})]} f t$ = $\sqrt{\frac{225}{4} - \frac{81}{4}} f t$ = $\sqrt{\frac{144}{4}}$ = 6ft

Area of closet =(6 x 4.5)sq.ft = 27 sq.ft

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Q:

In a 1 km race, A beats B by 28 meters in 7sec. Find A's time over the course?

A) 5min,4sec	B) 4min,3sec
C) 2min,3sec	D) 3min,4sec

Answer & Explanation Answer: B) 4min,3sec

Explanation:

B covers 28 meters in 7sec. So, B's time over the course = (7/28)*100 =250 sec.

Whereas A's time over the course = 250 -7 = 243 sec.

i.e A's time over the course is 4min , 3 sec.

Report Error

View Answer Report Error Discuss

Filed Under: Races and Games

Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 2.91 m	B) 3 m
C) 5.82 m	D) None of these

Answer & Explanation Answer: B) 3 m

Explanation:

Area of the park = (60 x 40) = 2400 sq.m

Area of the lawn = 2109 sq.m

Area of the crossroads = (2400 - 2109) = 291 sq.m

Let the width of the road be x metres. Then,

60x + 40x - (x * x) = 291

=>(x * x) - 100x + 291 = 0

=>(x - 97)(x - 3) = 0

=>x=3

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Q:

The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

A) 16cm	B) 18cm
C) 24cm	D) .Data inadequate

Answer & Explanation Answer: B) 18cm

Explanation:

2(l+b)/b = 5/1

=> 2l + 2b = 5b

=> 3b = 2l

=> b =(2/3) x l

Then, Area = 216 sq.cm

l x b = 216

=> l x [(2/3)x l] =216

=> l x l = 324

=> l = 18 cm.

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Q:

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

A) 2%	B) 2.02%
C) 4%	D) .4.04%

Answer & Explanation Answer: D) .4.04%

Explanation:

100 cm is read as 102 cm.

A1 = (100 x 100) and A2 =(102 x 102)

(A2 - A1) = [(102 x 102)-(100 x 100) ]= 404

Percentage error =[404/(100 x 100 )] x 100%= 4.04%

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

Searching for "M"

Quick Links