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Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is $7 C_{5}$ .

So,required probability = $7 C_{5}$ / $10 C_{5}$ = 1/12.

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Filed Under: Probability

Q:

A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb.

A) 5/12	B) 7/12
C) 3/14	D) 1/12

Answer & Explanation Answer: A) 5/12

Explanation:

Total number of elementary events = $10 C_{5}$

Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is $3 C_{1} * 7 C_{4}$

So,required probability = $3 C_{1} * 7 C_{4}$ / $10 C_{5}$ = 5/12.

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Q:

A is the brother of B. B is the brother of C. D is the father of A. Based on these three statements, which of the following statements cannot be definitely true ?

A) B is the brother of A.	B) B is the son of D.
C) A is the brother of C.	D) C is the brother of A.

Answer & Explanation Answer: D) C is the brother of A.

Explanation:

A is the brother of B and B is the brother of C. So, C may be the brother or sister of A.

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Filed Under: Blood Relations

Q:

What are the different types of Real-Time Scheduling?

Answer

Hard real-time systems required to complete a critical task within a guaranteed amount of time.
Soft real-time computing requires that critical processes receive priority over less fortunate ones.

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Subject: Operating Systems

Q:

E is the son of A. D is the son of B. E is married to C. C is B's daughter. How is D related to E ?

A) Brother	B) Uncle
C) Father-in-Law	D) Brother-in-law

Answer & Explanation Answer: D) Brother-in-law

Explanation:

C is D's daughter and D is B's son. So, D is the brother of C. E is a male married to C.

So, E is the husband of C, whose brother is D. So, D is the brother-in-law of E.

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Filed Under: Blood Relations

Q:

A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A) 551/15134	B) 1/2
C) 552/15379	D) 1/9

Answer & Explanation Answer: A) 551/15134

Explanation:

Total number of elementary events = $50 C_{5}$
Given,third ticket =30

=> first and second should come from tickets numbered 1 to 29 = $29 C_{2}$ ways and remaining two in $20 C_{2}$ ways.

Therfore,favourable number of events = $29 C_{2} * 20 C_{2}$

Hence,required probability = $29 C_{2} * 20 C_{2}$ $/ 50 C_{5}$ =551 / 15134

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Q:

Find the area of a square, one of whose diagonals is 3.8 m long.

A) 4.22 sq.m	B) 5.22 sq.m
C) 6.22 sq.m	D) 7.22 sq.m

Answer & Explanation Answer: D) 7.22 sq.m

Explanation:

Area of the square = $\frac{1}{2} \times {(d i a g o n a l)}^{2}$ = 1/2 * 3.8 * 3.8 = 7.22 sq.m

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What are the different job scheduling in operating systems?

Answer

Scheduling is the activity of the deciding when process will receive the resources they request.

FCS ---> FCSFS stands for First Come First Served. In FCFS the job that has been waiting the longest is served next.

Round Robin Scheduling--->Round Robin scheduling is a scheduling method where each process gets a small quantity of time to run and then it is preempted and the next process gets to run. This is called time-sharing and gives the effect of all the processes running at the same time

Shortest Job First ---> The Shortest job First scheduling algorithm is a nonpreemptive scheduling algorithm that chooses the job that will execute the shortest amount of time.

Priority Scheduling--->Priority scheduling is a scheduling method where at all times the highest priority process is assigned the resource.

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Subject: Operating Systems

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