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Q:

One card is drawn from a pack of 52 cards,each of the 52 cards being equally likely to be drawn.Find the probability that the ball drawn is an ace :

A) 1/13	B) 1/12
C) 1/14	D) 1/15

Answer & Explanation Answer: A) 1/13

Explanation:

Total number of events=52

Number of aces =4

So,required probability = 4/52 =1/13

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Filed Under: Probability

Q:

By investing Rs. 1620 in 8% stock, Michael earns Rs. 135. The stock is then quoted at:

A) 80	B) 96
C) 106	D) 108

Answer & Explanation Answer: B) 96

Explanation:

To earn Rs. 135, investment = Rs. 1620.

To earn Rs. 8, investment = $R s . \frac{1620}{135} \times 8$ = Rs. 96.

Market value of Rs. 100 stock = Rs. 96.

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Filed Under: Stocks and Shares

Q:

Three dice are thrown together.Find the probability of getting a total of atleast 6.

A) 103/216	B) 103/108
C) 103/36	D) 36/103

Answer & Explanation Answer: B) 103/108

Explanation:

Total number of events=6 x 6 x 6=216
Let A be the event of getting a total of atleast 6 and B denoted event of getting a total of less than 6 i.e.,3,4,5.

So,B={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)}

Favourable number of cases=10

Therefore,P(B)=10/216

=> P(A) = 1 - P(B)

= 1 - (10/216) = 103/108

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Filed Under: Probability

Q:

A man invests some money partly in 9% stock at 96 and partly in 12% stock at 120. To obtain equal dividends from both, he must invest the money in the ratio:

A) 3:5	B) 2:1
C) 16:15	D) 4:5

Answer & Explanation Answer: C) 16:15

Explanation:

For an income of Re. 1 in 9% stock at 96, investment = Rs. 96/9 = Rs.32/3

For an income Re. 1 in 12% stock at 120, investment = Rs. 120/12 = Rs. 10.

Ratio of investments =(32/3) : 10 = 32 : 30 = 16 : 15.

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Filed Under: Stocks and Shares

Q:

Sharon Stone deposits $2000 at the end of each year in an account earning 10% compounded annually. Determine how much money she has after 25 years. How much interest did she earn?

A) 146694.12	B) 13452
C) 18232	D) 15627

Answer & Explanation Answer: A) 146694.12

Explanation:

S=R[(1+i)^n-1]/i

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

The curved surface area of a cylindrical pillar is 264 sq.m and its volume is 924 cub.m. Find the ratio of its diameter to its height

A) 3 : 7	B) 7 : 3
C) 6 : 7	D) 7 : 6

Answer & Explanation Answer: B) 7 : 3

Explanation:

$\frac{{πr}^{2 h}}{2 {πr}^{2 h}} = \frac{924}{264}$

=> r = (24/364) x 2 = 7m

$2 πrh = 264 \Rightarrow h = (264 \times \frac{7}{22} \times \frac{1}{2} \times \frac{1}{7}) = 6 m$

Required Rato =2r/h =14/6 = 7:3

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Filed Under: Volume and Surface Area

Q:

What are the data units at different layers of the TCP / IP protocol suite?

Answer

The data unit created at the application layer is called a message, at the transport layer the data unit created is called either a segment or an user datagram, at the network layer the data unit created is called the datagram, at the data link layer the datagram is encapsulated in to a frame and finally transmitted as signals along the transmission media.

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Subject: Networking
Job Role: Network Engineer

Q:

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

A) 49	B) 50
C) 53.5	D) 55

Answer & Explanation Answer: A) 49

Explanation:

Area of the wet surface = [2(lb + bh + lh) - lb]

= 2(bh + lh) + lb

= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] $m^{2}$

= 49 $m^{2}$

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Filed Under: Volume and Surface Area

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