1. ANSWER : D 

Explanation -  Required difference 

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88. 

2. ANSWER : B 

Explanation -  Total number of Peons working in the Company in 1999 

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192. 

3. ANSWER : A 

Explanation - Number of Managers working in the Company: 

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers  

=1252-760760×100 %= 64.74%  

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians 

 = 1936-12001200×100 % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) -  (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators  

=1444-880880×100 % = 64.09% 

Number of Accountants working in the Company: 

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) -  (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants  

=1884-11601160×100 % = 62.14% 

Number of Peons working in the Company: 

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104)    = 1288.

Therefore, Percentage increase in the number of Peons  

=1288-820820×100 % = 57.07% 

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B 

Explanation  -  Total number of employees of various categories working in the Company in 1997 are: 

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D 

Explanation  - Total number of Operators who left the Company during 1995 - 2000 

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

1. ANSWER :   C 

Explanation -   34 x 3.6 = 122.4 (since 1% = 3.6 degrees)  

2. ANSWER :  B 

Explanation -   (67/11) x 4000 = 24 363.6364   

3. ANSWER :  C

Explanation -  (33 + 11) = 44 

4. ANSWER :  A

Explanation -  Investment other than NRI and corporate houses is 33% = 335000.  Also, investment by offshore funds and NRI's is equal to 27%.

 Hence, (27 x 335000)/33 = 274 090.909

5. ANSWER : B

Explanation -  FII's currently account for 33 out of 100.

If their value is doubled and all other investments are kept constant then their new value would be 66 out of 133 = approximately equal to 50%

As sales occurs every customer is not able to pay the bills that's where A/R are occurs the goal of A/R is to maintain summarize & record all the transactions related to unpaid a/c or future collections or A/R.

Variables that are defined in a C# program belong to two major categories: value type and reference type. The variables that are based on value type contain a value that is either allocated on a stack or allocated in-line in a structure. The variables that are based on reference types store the memory address of a variable, which in turn stores the value and are allocated on the heap. The variables that are based on value types have their own copy of data and therefore operations done on one variable do not affect other variables. The reference-type variables reflect the changes made in the referring variables.

It is a group of functions and implemented under algorithm header file.

There are four parameters. They are first1, last1, first2, predicate.

It is a method in the search opertion in standard library algorithms.

#include<stdio.h>

int main(){

  int a[10][10],i,j,sum=0,m,n;

  printf("\nEnter the row and column of matrix: ");
  scanf("%d %d",&m,&n);

  printf("\nEnter the elements of matrix: ");
  for(i=0;i<m;i++)
      for(j=0;j<n;j++)
           scanf("%d",&a[i][j]);
  printf("\nThe matrix is\n");

  for(i=0;i<m;i++){
      printf("\n");
      for(j=0;j<m;j++){
      printf("%d\t",a[i][j]);
      }
 }
 for(i=0;i<m;i++){
     for(j=0;j<n;j++){
          if(i==j)
              sum=sum+a[i][j];
     }
 }
 printf("\n\nSum of the diagonal elements of a matrix is: %d",sum);

 return 0;
}

Sample output:

Enter the row and column of matrix: 3 3
Enter the elements of matrix:
2
3
5
6
7
9
2
6
7
The matrix is
2       3       5
6       7       9
2       6       7
Sum of the diagonal elements of a matrix is: 16