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Q:

A man borrowed Rs 24000 from two money lenders. For one loan, he paid 15% per annum and for the other 18% per annum. At the end of one year, he paid Rs 4050. How much did he borrow at each rate ?

A) Rs.16000 B) Rs.12000
C) Rs.15000 D) Rs.13000
 
Answer & Explanation Answer: C) Rs.15000

Explanation:

Let the sum at 15% be Rs x and that at 18% be Rs (24000 - x).

{(x * 15 * 1)/100 } + { [(24000 – x) * 18 * 1]/100 } = 4050

or 15 x + 432000 - 18x = 405000 or x = 9000.

Money borrowed at 15% = Rs 9000 .

Money borrowed at 18% = Rs 15000.

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Q:

Simple interest on a certain sum is 16/25 of the sum. Find the rate percent and time, If both are numerically equal.

A) Rate = 7% and Time = 7 years. B) Rate = 8% and Time = 8 years.
C) Rate = 6% and Time = 6 years. D) Rate = 5% and Time = 5 years.
 
Answer & Explanation Answer: B) Rate = 8% and Time = 8 years.

Explanation:

Let sum = X. Then S.I = 16x/25

 

Let rate = R% and Time = R years.

 

Therefore,  (x * R * R)/100 = 16x/25   =>  R = 40/5 = 8

 

Therefore, Rate = 8% and Time = 8 years.

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Q:

A sum was put at simple interest at a certain rate for 3 years. Had it been put at 2% higher rate, it would have fetched Rs 360 more. Find the sum.

A) Rs.4000 B) Rs.9000
C) Rs.5000 D) Rs.6000
 
Answer & Explanation Answer: D) Rs.6000

Explanation:

Let sum = P and original rate = R. Then

[(P * (R+2) * 3)/100] - [ (P * R * 3)/100] = 360

3P*(R+2) - 3PR = 36000

3PR + 6P - 3PR = 36000

6P = 36000

P = 6000

 

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Q:

A certain sum of money amounts to Rs 1008 in 2 years and to Rs 1164 in 3 ½  years. Find the sum and the rate of interest.

A) 800, 14% B) 800, 13%
C) 800, 12% D) 800, 19%
 
Answer & Explanation Answer: B) 800, 13%

Explanation:

S.I. for 1 ½ years = Rs (1164 - 1008) = Rs 156 . 

S.I. for 2 years = Rs (156 x 23 x 2)= Rs 208. 

Therefore, Principal = Rs (1008 - 208) = Rs 800. 

Now, P = 800, T= 2 and S.I. = 208.

Therefore, Rate = (100 x S.I.) / (P x T) = [ (100 x 208)/(800 x 2)]% = 13%

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Q:

A sum at simple interest at 1312% per annum amounts to Rs. 2502.50 after 4 years. Find the sum

A) Rs.1625 B) Rs1525
C) Rs.1425 D) Rs.1325
 
Answer & Explanation Answer: A) Rs.1625

Explanation:

 Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50 

 

Amount =Rs [ x + (27x/50)] = Rs.77x/50 

 

=> 77X/50 = 2502.50  

 

=>X= (2502.50 * 50)/77 = 1625 

 

Hence Sum = Rs.1625

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Q:

Find: S.l. on Rs 3000 at 18% per annum for the period from 4th

A) 118 B) 105
C) 108 D) 110
 
Answer & Explanation Answer: C) 108

Explanation:

(24 + 31 + 18) days = 73 days = 1/5 year .

 

P = Rs 3000 and R = 18 % p.a.

 S.I=3000*18*15100

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Q:

What is the sum which earned interest?
I. The total simple interest was Rs. 7000 after 7 years.
II. The total of sum and simple interest was double of the sum after 5 years.

A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer D) Both I and II are necessary to answer
 
Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Let the sum be Rs. x.

I  gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

therefore, S.I. for 1 year =  Rs. 1000.

Thus, I and II both are needed to get the answer.

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Q:

1. The simple interest on a sum of money is Rs. 50. What is the sum?
I. The interest rate is 10% p.a.
II. The sum earned simple interest in 10 years

A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer D) Both I and II are necessary to answer
 
Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Given : S.I. = Rs. 50.

I  gives,  R = 10% p.a.

II gives,  T = 10 years.

Sum = (100 x S.I)/(t x r ) =  Rs.(100 x 50)/(10 x 10) = Rs.50

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