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Q:

Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?

A) 10 : 5	B) 15 : 2
C) 20 : 2	D) 25 : 2

Answer & Explanation Answer: D) 25 : 2

Explanation:

Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number.

US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.

Now US : Indian = 25 : 10, and Indian : British = 10 : 2

Hence the two ratios can be combined and US : British = 25 : 2

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Filed Under: Ratios and Proportions
Exam Prep: GRE

Q:

There are eight boxes of chocolates, each box containing distinct number of chocolates from 1 to 8. In how many ways four of these boxes can be given to four persons (one boxes to each) such that the first person gets more chocolates than each of the three, the second person gets more chocolates than the third as well as the fourth persons and the third person gets more chocolates than fourth person?

A) 70	B) 40
C) 72	D) 80

Answer & Explanation Answer: A) 70

Explanation:

All the boxes contain distinct number of chocolates.
For each combination of 4 out of 8 boxes, the box with the greatest number has to be given to the first person, the box with the second highest to the second person and so on.

The number of ways of giving 4 boxes to the 4 person is: 8 $C_{4}$ = 70

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Filed Under: Permutations and Combinations

Q:

From a deck of 52 cards, a 7 card hand is dealt.How many distinct hands are there if the hand must contain 2 spades and 3 diamonds ?

A) 7250100	B) 7690030
C) 7250000	D) 3454290

Answer & Explanation Answer: A) 7250100

Explanation:

There are 13 spades,we must include 2: 13 $C_{2}$

There are 13 diamonds,we must include 3: $13 C_{3}$

Since we can't have more than 2 spades and 3 diamonds,the remaining 2 cards must be pulled out from the 26 remaining clubs and hearts : $26 C_{2}$

Therefore, $13 C_{2} * 13 C_{3} * 26 C_{2}$ = 7250100

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Filed Under: Permutations and Combinations

Q:

A column defined as UNIQUE can contain Nulls while a column defined as PRIMARY KEY can't contain Nulls

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

Because a table can have only one primary key

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Subject: Oracle Certification
Job Role: Database Administration

Q:

There are 6 bowlers and 9 batsmen in a cricket club. In how many ways can a team of 11 be selected so that the team contains at least 4 bowlers?

A) 1170	B) 1200
C) 720	D) 360

Answer & Explanation Answer: A) 1170

Explanation:

Possibilities Bowlers Batsmen Number of ways

6 9

1 4 7 $(6 C_{4} * 9 C_{7})$

2 5 6 $(6 C_{5} * 9 C_{6})$

3 6 5 $(6 C_{6} * 9 C_{5})$

$(6 C_{4} * 9 C_{7})$ = 15 x 36 = 540

$(6 C_{5} * 9 C_{6})$ = 6 x 84 = 504

$(6 C_{6} * 9 C_{5})$ = 1 x 126 = 126

Total = 1170

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Filed Under: Permutations and Combinations

Q:

A subset of the database which contain virtual data that is derived from the database files but is not explicitly stored is called

A) Touple	B) View
C) Relation	D) Key

Answer & Explanation Answer: B) View

Explanation:

A view may be a subset of the database or it may contain virtual data that is derived from the database files but is not explicitly stored .

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Filed Under: Database
Job Role: Database Administration

Q:

A Map is an Array,which contains the addresses of the free space in swap device that are allocatable resources,and the number of the resource unit available there.

A) TRUE

B) FALSE

Answer & Explanation Answer: A) TRUE

Explanation:

The given statement is clearly true.

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Subject: Operating Systems
Exam Prep: GRE

Q:

A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?

A) 48	B) 64
C) 63	D) 45

Answer & Explanation Answer: B) 64

Explanation:

We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).

Required number of ways= $(3 C_{1} * 6 C_{2}) + (3 C_{2} * 6 C_{1}) + 3 C_{3}$ = (45 + 18 + 1) =64

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Filed Under: Permutations and Combinations

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