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Q:

Will the following function work?

f1 ( int a, int b )

{

    return ( f2 (20) );

}

f2 ( int a )

{

    return ( a * a );

}

Answer

Yes

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Subject: Programming

Q:

Point out the error, if any, in the following program.

main()

{

    int a = 10;

    void f();

    a = f();

    printf ( "\n %d", a );

}

void f()

{

    printf ( "\n Hi ");

}

Answer

In spite of defining the function f() as returning void, the program is trying to collect the value returned by f() in the variable a.

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Subject: Programming

Q:

There is a mistake in the following code. Add a statement in it to remove it.

main()

{

     int a;

     a = f (10, 3.14) ;

     printf ( " %d ", a );

}

f (int aa, float bb)

{

    return ( ( float ) aa + bb );

}

Answer

Add the following function prototype in main ():


float f ( int, float );

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

    float a = 0.7;

    if ( a < 0.7f )

          printf ( " C ");

    else 

          Printf ( " C++ ");

}

Answer

C++

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Subject: Programming

Q:

If the binary equivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what would be the output of the following program?

main()

{

    float a = 5.375 ;

    char *p;

    int i;

    p = ( char* ) &a ;

    for ( i = 0; i <= 3 ; i++ )

          printf ( " %02x ", (unsigned char ) p[i] );

}

Answer

00 00 AC 40

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Subject: Programming

Q:

What would be the output of the following program?

main()

{

    printf (" %d%d%d ", sizeof (3.14f), sizeof (3.14), sizeof (3. 141);

}

Answer

4  8  10

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Subject: Programming

Q:

Which error are you likely to get when you run the following program?

main()

{

  struct emp

  {

      char name[20];

      float sal;

  };

  struct emp e[10];

  int i;

  for ( i = 0 ; i <= 9; i++)

        scanf ( "%s %f" , e[i].name, &e[i].sal );

}

Answer

Floating point formats not linked

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Subject: Programming

Q:

We want to round off x, a Float to an Int value. The correct way to do so would be

A) Y = ( int ) ( x + 0.5 ) ; B) Y = int ( x + 0.5) ;
C) Y = ( int ) x + 0.5; D) Y = ( int ) ( ( int ) x + 0.5 )
 
Answer & Explanation Answer: A) Y = ( int ) ( x + 0.5 ) ;

Explanation:

Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.

 

y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)

 

Example:

 

#include

 

int main ()

 

{

 

  float x = 2.6;

 

  int y = (int)(x + 0.5);

 

  printf ("Result = %d\n", y );

 

  return 0;

 

}

 

Result : 3

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Filed Under: Programming