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Q:

Alloy A contains 40% gold and 60% silver. Alloy B contains 35% gold and 40% silver and 25% copper. Alloys A and B are mixed in the ratio of 1:4 .What is the ratio of gold and silver in the newly formed alloy is?

A) 20% and 30%	B) 36% and 44%
C) 25% and 35%	D) 49% and 36%

Answer & Explanation Answer: B) 36% and 44%

Explanation:

Assume the weight of alloy a is 100 kg

Therefore, The weight of alloy B is 400kg

Gold silver copper

A 40kg 60kg 0kg

B 140kg 160kg 100kg

total 180kg 220kg 100kg

Therefore, Ratio of gold and silver in new alloy = $\frac{180}{500} : \frac{200}{500}$ = 36% :44%

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Q:

The number of oranges in three baskets are in the ratio of 3 : 4 : 5. In which ratio the no. of oranges in first two baskets must be increased so that the new ratio becomes 5 : 4 : 3?

A) 1:3	B) 2:1
C) 3:4	D) 2:3

Answer & Explanation Answer: B) 2:1

Explanation:

Let, B1 : B2 : B3 = 3x : 4x : 5x

again B1 : B2 : B3 = 5y : 4y : 3y

Since there is increase in no.of oranges in first two baskets only, it means the no. of oranges remains constant in the third basket

Therefore, 5x = 3y

Hence 3x : 4x : 5x => $\frac{9 y}{5} : \frac{12 y}{5} : \frac{15 y}{5}$ = 9y:12y:15y

and 5y : 4y : 3y => 25x : 20x : 15x

Therfore, increment in first basket = 16

Increment in second basket = 8

Thus, required ratio = 16/8 = 2:1

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Q:

In a zoo, there are rabbits and pigeons. If heads are counted, there are 340 heads and if legs are counted there are 1060 legs.How many pigeons are there?

A) 120	B) 150
C) 170	D) 180

Answer & Explanation Answer: B) 150

Explanation:

Suppose there are all the pigeons then total no of heads are 340 and total no of legs are 680.

Now, since 380 (1060-680) legs are extra, it means there will be 190 (380/2) rabbits.As we know a rabbit has two extra legs than that of a pigeon.

Therefore, number of rabbits =190

and number of pigeons = 340- 190 = 150

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Q:

In Maa Yatri Temple every devotee offers fruits to the orphans. Thus every orphan receives bananas, oranges and grapes in the ratio of 3:2:7 in terms of dozens. But the weight of a grape is 24 gm and weight of a banana and an orange are in the ratio of 4:5, while the weight of an orangeis 150gm. Find the ratio of all the three fruits in terms of weight, that an orphan gets

A) 90:75:42	B) 180:150:82
C) 75:42:90	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

Ratio of fruits (by dozen) = 3:2:7

Ratio of fruits (by weight) = 120 :150: 24

Therefore, Ratio of fruits (combined) by weight = 3 x 120 : 2 x 150 : 7 x 24 = 30 : 25 : 14

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Q:

Pooja, Shipra and Mounika are three sisters .Pooja and Shipra are twins. The ratio of sum of the ages of Pooja and Shipra is same as that of Mounika alone. Three years earlier the ratio of age of Pooja and Mounika was 2:7 . what will be the age of Shipra 3 years hence?

A) 21 years	B) 16 years
C) 8 years	D) 12 years

Answer & Explanation Answer: C) 8 years

Explanation:

Since Pooja and Shipra are twins so their ages be same. Let their ages be x and age of Mounika be y , then

x+x = y -------(1)

and $\frac{x - 3}{y - 3} = \frac{2}{7} \Rightarrow 7 x - 2 y = 15$

Now, from equation (1),

7x - 4x = 15 => x = 5

So the age of Shipra 3 years hence will be 5+3 = 8 years

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Q:

Three cats are roaming in a zoo n such a way that when cat A takes 5 steps, B takes 6 steps and C takes 7 steps.But the 6 steps of A are equal to the 7 steps of B and 8 steps of C. what is the ratio of their speeds?

A) 140:144:147	B) 40:44:47
C) 15:21:28	D) 252:245:240

Answer & Explanation Answer: A) 140:144:147

Explanation:

Frequency of step of A:B:C = 5 : 6 : 7

But in terms of size of step, 6A = 7B = 8C

Therefore, Ratio of speeds of A, B and C = 5/6 : 6/7 : 7/8 = 140 : 144 : 147

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Q:

At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?

A) Rs.2500	B) Rs.2000
C) Rs.4000	D) None of these

Answer & Explanation Answer: C) Rs.4000

Explanation:

Maximum earning will be only when he will won on the maximum yielding table.

A ----> 10:1

B ----> 20:1

C ----> 30:1

i.e, he won on B and C but lost on A

20 x 200 + 30 x 200 -1 x 200 = 9800

minimum earning will be when he won on table A and B and lose on that table 3.

Therefore, 10 x 200 + 20 x 200 - 1 x 200 = 6000-200 = 5800

Therefore, Difference= 9800 - 5800 = 4000

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Q:

The ratio of students in a coaching preparing for B.tech and MBA is 4 : 5. The ratio of fees collected from each of B.tech and MBA students is 25 : 16. If the total amount collected from all the students is 1.62 lakh, what is the total amount collected from omly MBA aspirants?

A) Rs. 62,000	B) Rs. 72,000
C) Rs. 82,000	D) None of these

Answer & Explanation Answer: B) Rs. 72,000

Explanation:

The ratio of fees collected from B.Tech : MBA = 4x * 25y : 5x * 16y

= 100xy : 80xy

= 5xy : 4 xy = 5k : 4k

The amount collected only from MBA students = $\frac{4}{9} \times 1.62 l a k h$ = Rs. 72,000

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