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Q:

Which calendar was used again in the year 1856?

A) 1828	B) 1850
C) 1830	D) 1852

Answer & Explanation Answer: A) 1828

Explanation:

Given year 1856, when divided by 4 leaves a remainder of 0.

NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.

So, 1856 - 28 = 1828

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Filed Under: Calendar

Q:

The calendar of year 1939 is same as which year?

A) 1943	B) 1964
C) 1950	D) 1956

Answer & Explanation Answer: C) 1950

Explanation:

Given year 1939, when divided by 4 leaves a remainder of 3.

NOTE: When remainder is 3, 11 is added to the given year to get the result.

So, 1939 + 11 = 1950

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Filed Under: Calendar

Q:

The year next to 2003 will have the same calendar as that of the year 2003?

A) 2024	B) 2014
C) 2009	D) 2020

Answer & Explanation Answer: B) 2014

Explanation:

Given year 2003, when divided by 4 leaves a remainder of 3.

NOTE: When remainder is 3, 11 is added to the given year to get the result.

So, 2003 + 11 = 2014

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Filed Under: Calendar

Q:

The calendar of the year 1897 can be used again in the year?

A) 1908	B) 1901
C) 1903	D) 1926

Answer & Explanation Answer: C) 1903

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2: Add +6 to the Given Year.

Solution :

Given Year is 1897, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 1897 + 11) = 1908, Which is a leap year.

Step 2 : Add +6 to the given year (i.e 1897 + 6) = 1903

Therfore, The calendar of the year 1897 can be used again in the year 1903

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Filed Under: Calendar

Q:

The calendar of year 1856 is same as which year?

A) 1883	B) 1884
C) 1864	D) 1880

Answer & Explanation Answer: B) 1884

Explanation:

Given year 1856, when divided by 4 leaves a remainder of 0.

NOTE: When remainder is 0, 28 is added to the given year to get the result.

So, 1856 + 28 = 1884

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Filed Under: Calendar

Q:

If log 2 = 0.3010 and log 3 = 0.4771, the values of log₅ 512 is

A) 2.875	B) 3.875
C) 4.875	D) 5.875

Answer & Explanation Answer: B) 3.875

Explanation:

ANS: log₅512 = log512/log5 = $\frac{\log 2^{9}}{\log (10 / 2)}$ = $\frac{9 \log 2}{\log 10 - \log 2}$ = $\frac{9 * 0.3010}{1 - 0.3010}$ =2.709/0.699 =2709/699 =3.876

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?

A) 11 4/11	B) 13 4/11
C) 15 4/11	D) 16 4/11

Answer & Explanation Answer: D) 16 4/11

Explanation:

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.
To be coincident, it must gain 15 min. spaces.55 min. are gained in 60 min.
15 min. are gained in
= (60/55 x 15)min
=16+4/11
The hands are coincident at 16 + 4/11 min past 3

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

How much does a watch lose per day, if its hands coincide ever 64 minutes?

A) 32 8/11	B) 33 8/11
C) 34 8/11	D) 35 8/11

Answer & Explanation Answer: A) 32 8/11

Explanation:

55min spaces are covered in 60min

60 min. spaces are covered in (60/55 x 60) min= 65+5/11 min.

loss in 64min=(65+5/11)- 64 =16/11

Loss in 24 hrs (16/11 x 1/64 x 24 x 60) min= 32 8/11.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

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