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Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 40	B) 120
C) 50	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

Let breadth = x metres.

Then, length = (x + 20) metres.

Perimeter = 5300 m = 200 m. 26.50

2[(x + 20) + x] = 200

2x + 20 = 100

2x = 80

x = 40.

Hence, length = x + 20 = 60 m.

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Filed Under: Volume and Surface Area

Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 25% increase	B) 50% increase
C) 50% decrease	D) 75% decrease

Answer & Explanation Answer: B) 50% increase

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x/2 and New breadth = 3y.

New area = (x/2 * 3y) = (3/2 )xy

Therefore, Increase % = [(1/2)xy * (1/xy) * 100] % = 50%

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Filed Under: Volume and Surface Area

Q:

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A) 1520 sq.m	B) 2420 sq.m
C) 2480 sq.m	D) 2520 sq.m

Answer & Explanation Answer: D) 2520 sq.m

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) sq.m

= 2520 sq.m

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Q:

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

A) 814	B) 820
C) 840	D) 844

Answer & Explanation Answer: A) 814

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) sq.cm

Required number of tiles = 1517 x (902/41) x 41 = 814

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Filed Under: Volume and Surface Area

Q:

The diagonal of a rectangle is sqrt(41) cm. and its area is 20 sq. cm. The perimeter of the rectangle must be:

A) 9 cm	B) 18 cm
C) 20 cm	D) 41 cm

Answer & Explanation Answer: B) 18 cm

Explanation:

$l^{2} + b^{2}$ = ${(d i a g o n a l)}^{2}$ =40

Also, lb=20

${(l + b)}^{2} = l^{2} + b^{2} + 2 l b$ = 41 + 40 =81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

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Filed Under: Volume and Surface Area

Q:

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

A) 10%	B) 10.08%
C) 20%	D) 28%

Answer & Explanation Answer: D) 28%

Explanation:

Let original length = x and original breadth = y.

Decrease in area = xy -[(80/100x) * (90/100y)]

=[(xy-(18/25)xy)]

=(7/25)xy

Decrease % =[(7/25)xy * (1/xy) * 100] =28%

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Filed Under: Volume and Surface Area

Q:

The diagonal of the floor of a rectangular closet is $7 \frac{1}{2}$ feet. The shorter side of the closet is $4 \frac{1}{2}$ feet. What is the area of the closet in square feet?

A) 5 .5	B) 13.5
C) 27	D) 37

Answer & Explanation Answer: C) 27

Explanation:

Other side= $\sqrt{[{(\frac{15}{2})}^{2} - (\frac{9^{2}}{2})]} f t$ = $\sqrt{\frac{225}{4} - \frac{81}{4}} f t$ = $\sqrt{\frac{144}{4}}$ = 6ft

Area of closet =(6 x 4.5)sq.ft = 27 sq.ft

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Filed Under: Volume and Surface Area

Q:

In a 1 km race, A beats B by 28 meters in 7sec. Find A's time over the course?

A) 5min,4sec	B) 4min,3sec
C) 2min,3sec	D) 3min,4sec

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