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Q:

A cow s tethered in the middle of a field with a 14feet long rope.If the cow grazes 100 sq feet per day, then approximately what time will be taken by the cow to graze the whole field?

A) 616	B) 716
C) 816	D) 516

Answer & Explanation Answer: A) 616

Explanation:

area of the field grazed = (22/7) * 14 * 14 = 616 sq feet

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Q:

A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field?

A) 220/7 min	B) 110/7 min
C) 90/7 min	D) 230/7 min

Answer & Explanation Answer: A) 220/7 min

Explanation:

speed = 12 km/h = $12 \times \frac{5}{18} = \frac{10}{3} m / s$

distance covered = $20 \times 2 \times \frac{22}{7} \times 50 = \frac{44000}{7} m$

time taken = distance /speed = $\frac{44000}{7} \times \frac{3}{10} s e c = \frac{4400 \times 3}{7} \times \frac{1}{60} m i n = \frac{220}{7} m i n$

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Q:

The area of a circle of radius 5 is numerically what percent its circumference?

A) 150%	B) 250%
C) 350%	D) 450%

Answer & Explanation Answer: B) 250%

Explanation:

required percentage = $\frac{{πr}^{2}}{2 πr} \times 100 = 250$ %

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Q:

The area of a field in the shape of a trapezium measures 1440sq m. The perpendicular distance between its parallel sides is 24cm. If the ratio of the sides is 5:3, the length of the longer parallel side is:

A) 75	B) 85
C) 95	D) 105

Answer & Explanation Answer: A) 75

Explanation:

Area of field = $\frac{1}{2} * (5 x + 3 x) * 24$ = 96x sq.m

96x = 1440 => x = $\frac{1440}{96}$ = 15

Hence, the length of longer parallel side = 5x = 75m

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Q:

If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:

A) 1:1	B) 1:2
C) 1:3	D) 1:4

Answer & Explanation Answer: A) 1:1

Explanation:

A square and a rhombus on the same base are equal in area

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Q:

If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

A) 10	B) 11
C) 12	D) 13

Answer & Explanation Answer: D) 13

Explanation:

Area = $\frac{1}{2} * d i a g o n a l 1 * \frac{1}{2} d i a g o n a l 2$ = $\frac{1}{2} * 24 * 10$ sq.cm

$\frac{1}{2} * d a i g o n a l 1 = \frac{1}{2} * 24 = 12 c m$

$\frac{1}{2} * d i a g o n a l 2 = \frac{1}{2} * 10 = 5 c m$

side of a rhombus = (12)² + (5)² = 169 => AB = 13cm

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Q:

If a parallelogram with area p, a triangle with area R and a triangle with area T are all constructed on the same base and all have the same altitude, then

A) P=R	B) P=A
C) P=A/2	D) P=2R

Answer & Explanation Answer: A) P=R

Explanation:

let each have base = b and height = h
then p = b*h, R = b*h and T = (1/2) * b*h
so P = R, P = 2T and T = (1/2)*R are all correct statements

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Q:

A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

A) 136	B) 236
C) 336	D) 436

Answer & Explanation Answer: C) 336

Explanation:

let ABCD be the given parallelogram

area of parallelogram ABCD = 2 x (area of triangle ABC)

now a = 30m, b = 14m and c = 40m

s=1/2 x (30+14+40) = 42

Area of triangle ABC = $\sqrt{[s (s - a) (s - b) (s - c)]}$

= $\sqrt{[42 (12) (28) (2)]}$ = 168sq m

area of parallelogram ABCD = 2 x 168 = 336 sq m

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