% Search

Q:

A sum at simple interest at $13 \frac{1}{2}$ % per annum amounts to Rs. 2502.50 after 4 years. Find the sum

A) Rs.1625	B) Rs1525
C) Rs.1425	D) Rs.1325

Answer & Explanation Answer: A) Rs.1625

Explanation:

Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50

Amount =Rs [ x + (27x/50)] = Rs.77x/50

=> 77X/50 = 2502.50

=>X= (2502.50 * 50)/77 = 1625

Hence Sum = Rs.1625

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

Q:

Find: S.l. on Rs 3000 at 18% per annum for the period from 4th

A) 118	B) 105
C) 108	D) 110

Answer & Explanation Answer: C) 108

Explanation:

(24 + 31 + 18) days = 73 days = 1/5 year .

P = Rs 3000 and R = 18 % p.a.

$S . I = (\frac{3000 * 18 * \frac{1}{5}}{100})$

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

Q:

Find: S.l. on Rs 6250 at 14% per annum for 146 days.

A) Rs.350	B) Rs.450
C) Rs.550	D) Rs.650

Answer & Explanation Answer: A) Rs.350

Explanation:

P = Rs. 6250, R = 14 % & T = (146/365) years = 2/5 years .

S.I= $R s . [\frac{6250 * 14 * \frac{2}{5}}{100}] = R s . 350$

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

Q:

Find: S.l on Rs 68000 at $16 \frac{2}{3}$ 1 % per annum for 9 months

A) 6500	B) 7500
C) 8500	D) 9500

Answer & Explanation Answer: C) 8500

Explanation:

P = 68000, R = $\frac{50}{3}$ % & T = 9 months (3/4 years)

$S . I = \frac{p \times r \times t}{100} = [\frac{(6800 \times \frac{50}{3} \times \frac{3}{4})}{100}] = R s . 8500$

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

Q:

What is the sum which earned interest?
I. The total simple interest was Rs. 7000 after 7 years.
II. The total of sum and simple interest was double of the sum after 5 years.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Let the sum be Rs. x.

I gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

therefore, S.I. for 1 year = Rs. 1000.

Thus, I and II both are needed to get the answer.

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

Q:

1. The simple interest on a sum of money is Rs. 50. What is the sum?
I. The interest rate is 10% p.a.
II. The sum earned simple interest in 10 years

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Given : S.I. = Rs. 50.

I gives, R = 10% p.a.

II gives, T = 10 years.

Sum = (100 x S.I)/(t x r ) = Rs.(100 x 50)/(10 x 10) = Rs.50

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE

Q:

A father left a will of Rs.35 lakhs between his two daughters aged 8.5 and 16 such that they may get equal amounts when each of them reach the age of 21 years. The original amount of Rs.35 lakhs has been instructed to be invested at 10% p.a. simple interest. How much did the elder daughter get at the time of the will?

A) 17.5 lakhs	B) 21 lakhs
C) 15 lakhs	D) 20 lakhs

Answer & Explanation Answer: B) 21 lakhs

Explanation:

Let Rs.x be the amount that the elder daughter got at the time of the will. Therefore, the younger daughter got (3,500,000 - x).

The elder daughter’s money earns interest for (21 - 16) = 5 years @ 10% p.a simple interest.

The younger daughter’s money earns interest for (21 - 8.5) = 12.5 years @ 10% p.a simple interest.

As the sum of money that each of the daughters get when they are 21 is the same,

$x + \frac{5 * 10 * x}{100} = (3, 500, 000 - x) + \frac{12.5 * 10 * (3, 500, 000 - x)}{100}$

$x + \frac{50}{x} = 3, 500, 000 - x + \frac{125}{100} * 3, 500, 000 - \frac{125 x}{100}$

$2 x + \frac{50 x}{100} + \frac{125 x}{100} = 3, 500, 000 * (1 + \frac{5}{4})$

$\frac{200 x + 50 x + 125 x}{100} = \frac{9}{4} * (3, 500, 000)$

=> $x = 2, 100, 000 = 21 l a k h s$

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE

Q:

A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at $6 \frac{1}{4}$ p.a for 2 years. Find his gain in the transaction per year

A) Rs. 112.50	B) Rs.150.25
C) Rs.167.50	D) Rs.170

Answer & Explanation Answer: A) Rs. 112.50

Explanation:

$g a i n i n 2 y e a r s = R s . [(5000 * \frac{25}{4} * \frac{2}{100}) - (\frac{5000 * 4 * 2}{100})]$

= Rs. (625 - 400)

= Rs. 225

$g a i n i n 1 y e a r = R s . (\frac{225}{2}) = 112.50$

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Searching for "%"

Quick Links