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Q:

In the history of Indian population, Which duration period is referred to as ' a great leap forward '

A) 1921 - 1931 B) 1941 - 1951
C) 1951 - 1961 D) 1971 - 1981
 
Answer & Explanation Answer: C) 1951 - 1961

Explanation:
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Filed Under: Indian Economy

Q:

The number 0.127 is how much greater than 1/8 ?

A) 1/100 B) 1/1500
C) 1/2 D) 1/500
 
Answer & Explanation Answer: D) 1/500

Explanation:

0.127 expressed as a fraction = 127/1000

1/8 can also be expressed as (1 x 125) / (8 x 125) = 125/1000

The difference is 2/1000, which is 1/500

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Filed Under: Decimal Fractions
Exam Prep: GRE

Q:

 What is the greatest of 3 consecutive integers whose sum is 24 ?

A) 6 B) 7
C) 8 D) 9
 
Answer & Explanation Answer: D) 9

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3

If the sum is 24, we need to solve the equation 3n + 3 = 24;

=> 3n = 21;

=> n = 7

The greatest of the three numbers is therefore 7 + 2 = 9

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Filed Under: Numbers
Exam Prep: GRE

Q:

For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?

A) 48 B) 49
C) 50 D) 51
 
Answer & Explanation Answer: C) 50

Explanation:

1 < 4n + 7 < 200

n can be 0, or -1

n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1.

The largest value for n will be an integer < (200 - 7) /4

193/4 = 48.25, hence 48

The number of integers between -1 and 48 inclusive is 50

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Filed Under: Numbers
Exam Prep: GRE

Q:

-20 , -16 , -12 , -8 .... 

In the sequence above, each term after the first is 4 greater than the preceding term. Which of the following could not be a term in the sequence? 

A) 220 B) 440
C) 668 D) 762
 
Answer & Explanation Answer: D) 762

Explanation:

All terms in the sequence will be multiples of 4.

762 and 902 are not multiples of 4

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Filed Under: Sequential Output Tracing
Exam Prep: GRE

Q:

Of the following, which is greater than ½ ?

Indicate ALL such fractions.

A) 2/5 B) 4/7
C) 4/9 D) 5/11
 
Answer & Explanation Answer: B) 4/7

Explanation:

One way to deal with fractions is to convert them all to decimals. 

In this case all you would need to do is to see which is greater than 0.5.

Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7. 

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Filed Under: Average
Exam Prep: GRE

Q:

How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed?

A) 376 B) 375
C) 500 D) 673
 
Answer & Explanation Answer: A) 376

Explanation:

The smallest number in the series is 1000, a 4-digit number.

 

The largest number in the series is 4000, the only 4-digit number to start with 4. 

 

The left most digit (thousands place) of each of the 4 digit numbers other than 4000 can take one of the 3 values 1 or 2 or 3.

 

The next 3 digits (hundreds, tens and units place) can take any of the 5 values 0 or 1 or 2 or 3 or 4.

 

Hence, there are 3 x 5 x 5 x 5 or 375 numbers from 1000 to 3999.

 

Including 4000, there will be 376 such numbers.

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Filed Under: Permutations and Combinations

Q:

Suppose you have a computional circuit between two registers driven by a clock. What will you do if the delay of the combinational circuit is greater than your clock signal?

Answer

Use the concept of register-retiming.


divide the totla combinatorial delay in two segments such that individually the delay is less the clock period.


this can be done by inserting a flip-flop in the combinational path.


e.g.,


clock period --- 5 ns


total cominational delay ---- 7


then divide the 7ns path in two path of 4 or 3 (best resutls are obtained if delays are  same for both path i.e 3.5ns) by inserting a flip-flop in between.

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Subject: Hardware