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Q:

A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?

A) 65m	B) 45m
C) 55m	D) 56m

Answer & Explanation Answer: D) 56m

Explanation:

perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m

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Q:

The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter

A) Rs.16500	B) Rs.15500
C) Rs.17500	D) Rs.18500

Answer & Explanation Answer: A) Rs.16500

Explanation:

l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500

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Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m	B) 16m
C) 14m	D) 76m

Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts

then, ${πr}^{2} = 9856 \Rightarrow r^{2} = \frac{9856 \times 7}{22} = 3136 \Rightarrow r = 56 m$

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Q:

If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

A) a	B) a>b
C) a=b	D) none

Answer & Explanation Answer: B) a>b

Explanation:

Take a square of side 4cm and a rectangle having l=6cm and b=2cm

then perimeter of square = perimeter of rectangle

area of square = 16 sq.cm

area of rectangle = 12 sq.cm

Hence a >b

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Q:

A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?

A) 10%	B) 20%
C) 30%	D) 40%

Answer & Explanation Answer: C) 30%

Explanation:

let the side of the square be x meters
length of two sides = 2x meters
diagonal = $\sqrt{2 x}$ = 1.414x m

saving on 2x meters = .59x m

saving % = $\frac{0.59 x}{2 x} * 100$ %

= 30% (approx)

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Q:

A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

A) rs.58	B) rs.158
C) rs.258	D) rs.358

Answer & Explanation Answer: C) rs.258

Explanation:

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m

cost of graveling = 344 x (75/100) = Rs. 258

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Q:

Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is

A) 12	B) 32
C) 42	D) 52

Answer & Explanation Answer: C) 42

Explanation:

required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm

= 196 - 154 = 42 sq.cm.

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Q:

Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is

A) 1.967	B) 1.867
C) 1.767	D) 1.567

Answer & Explanation Answer: A) 1.967

Explanation:

required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with Ã = 60 degrees and r = 3.5cm)
$(\frac{\sqrt{3}}{4} * 7 * 7) - (3 * \frac{22}{7} * 3.5 * 3.5 * \frac{60}{360})$ sq cm

= $(\frac{\sqrt{3}}{4} * 49) - (11 * 0.5 * 3.5)$ sq cm

= 1.967 sq cm

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