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Q:

An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metre of cloth ?

A) 194 seconds	B) 195 seconds
C) 196 seconds	D) 197seconds

Answer & Explanation Answer: B) 195 seconds

Explanation:

Let the time required by x seconds.

Then, More cloth means More time (Direct Proportion)

So, 0.128 : 1 :: 25 : x

$\Rightarrow x = \frac{1 \times 25}{0.128}$ => x = 195.31

So time will be approx 195 seconds

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Filed Under: Chain Rule

Q:

Sekar started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajeev joined him with an amount of Rs. 35,000. In 2001, Sekar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000. What will be Rajeev's share in the profit of Rs.1,50,000 earned at the end of 3 years from the start of the business in 1999?

A) Rs. 45,000	B) Rs. 50,000
C) Rs. 70,000	D) Rs. 75,000

Answer & Explanation Answer: B) Rs. 50,000

Explanation:

Sekar: Rajeev: jatin = (25000×12+35000×12+45000×12):(35000×24) : (35000×12)

= 1260000 : 840000 : 420000

= 3 : 2 : 1.

Rajeev's Share =Rs.(150000×2/6)

=Rs.50000.

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Filed Under: Partnership

Q:

A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution in the capital?

A) Rs. 7500	B) Rs. 8000
C) Rs. 8500	D) Rs. 9000

Answer & Explanation Answer: D) Rs. 9000

Explanation:

Let B's capital be Rs. x.

Then, $[\frac{3500 \times 12}{7 x} = \frac{2}{3}]$

=> 14x = 126000

=> x = 9000.

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Filed Under: Partnership

Q:

A, B, C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent?

A) Rs. 45	B) Rs. 50
C) Rs. 55	D) Rs. 60

Answer & Explanation Answer: A) Rs. 45

Explanation:

A:B:C = (10×7):(12×5):(15×3)

= 70 :60 :45

= 14 :12 :9

C's rent = Rs.(175×9/35)

=Rs. 45.

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Filed Under: Partnership

Q:

Bhajan Singh purchased 120 reams of paper at Rs 80 per ream. He spent Rs 280 on transportation, paid octroi at the rate of 40 paise per ream and paid Rs 72 to the coolie. If he wants to have a gain of 8 %, what must be the selling price per ream?

A) 90	B) 89
C) 87.48	D) 86

Answer & Explanation Answer: A) 90

Explanation:

Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90.

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Filed Under: Profit and Loss

Q:

A shopkeeper cheats to the extent of 10% while buying and selling, by using false weights. His total gain is.

A) 20%	B) 21%
C) 22%	D) 23%

Answer & Explanation Answer: B) 21%

Explanation:

Gain % = $(\frac{{(100 + c o m m o n g a i n %)}^{2}}{100} - 100)$ %

= $(\frac{{(100 + 10)}^{2}}{100} - 100)$

= 21%

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Filed Under: Profit and Loss

Q:

How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?

A) 36 Kg	B) 42 Kg
C) 54 Kg	D) 63 Kg

Answer & Explanation Answer: D) 63 Kg

Explanation:

By the rule of alligation:

C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind

Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.

Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.

Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.

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Filed Under: Alligation or Mixture

Q:

The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is

A) 15 cm	B) 25 cm
C) 35 cm	D) 42 cm

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